the guy Posted June 15, 2009 Posted June 15, 2009 what do you get when you add sodium hydroxide to urea? what is the equation?
UC Posted June 16, 2009 Posted June 16, 2009 (edited) http://www.chemguide.co.uk/organicprops/amides/hydrolysis.html Urea is just carbonic acid diamide. Edited June 16, 2009 by UC
bob000555 Posted July 25, 2009 Posted July 25, 2009 I am fairly sure urea is actually a special case. So the reaction of urea with sodium hydroxide is a bit more complex then is described in the article. Urea can be produced produced by the reaction of sodium cyanate (NaOCN) with ammonium chloride. NaOCN + NH4Cl -> NH2CONH2 + NaCl by adding NaOH to urea you are essentially reversing the process and will get sodium cyanate, ammonia and water. NaOH + (NH2)2CO -> NaOCN + NH3 + H2O
UC Posted July 27, 2009 Posted July 27, 2009 I am fairly sure urea is actually a special case. So the reaction of urea with sodium hydroxide is a bit more complex then is described in the article. Urea can be produced produced by the reaction of sodium cyanate (NaOCN) with ammonium chloride.NaOCN + NH4Cl -> NH2CONH2 + NaCl by adding NaOH to urea you are essentially reversing the process and will get sodium cyanate, ammonia and water. NaOH + (NH2)2CO -> NaOCN + NH3 + H2O References, if you please. Cyanic acid undergoes nucleophilic attack at the carbon by ammonia, followed by tautomerization, yielding urea. Simply adding something like NaOH will not reverse the reaction mechanism. The hydrolysis of urea proceeds like normal base-catalyzed amide hydrolysis, giving first sodium carbamate and ammonia. The carbamate readily undergoes a second hydrolysis reaction to give sodium carbonate and another equivalent of ammonia.
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