Continuing the calculations by Mordred and swansont:
The sun's spectrum peaks in the visible range, so let's guess that its visible output is on the order of 1025J/sec.
The energy of a visible photon is roughly hf = 10-33Jsec * 1017/sec = 10-16J.
So the output of visible photons is 1025J/sec / 10-16J = 1049 per second.
One light-year = 3*108m/sec * 3600 * 24 * 365 sec = 1016m.
The diameter of our galaxy is D = 100,000 light-years = 1021m.
The area of the spherical shell the photons pass through is roughly 10 D2 = 1043m2.
The area of a 6-inch telescope is about 0.01 m2.
So the area ratio is 10-2 / 1043 = 10-45.
And finally, the rate at which visible photons reach the telescope from a star on the other side of the Milky Way is:
10-45 * 1049/sec = somewhere in the vicinity of 10,000 visible photons per second.
Of course, this is only a rough guess, and different stars have different parameters, so let's say it's probably at least about 1000 per second, and maybe as many as 100,000, for an amateur telescope and an average star somewhere in the middle of the galaxy.