Sensei

I have better puzzle: you're tree. If somebody cut branch, put in ground, new tree will grow. How old are they? Suppose so, tree the next year, will have couple new branches. We will cut again to couple new plants. How old are they? I did it with my Aronia. Should I measure their age from the moment of cutting and putting to ground as separate plant? Or should I count it from when it used to be part of bigger tree before cutting.. ?

Not at all. There are eternal profits and terrestrial profits. If there would be opened US branch of company (not to mention South American branch), it would allow helping people in South America (because shorter distance of flight than from Europe). Which would open completely new market, wouldn't it? You don't know who you're helping. Suppose so some grand-grand father/mother of Einstein-to-be, Pasteur-to-be (or other fruitful scientist) in the next centuries, is poor and ill, can't pay for treatment, you can save entire human race, by helping his/her ancestors. In business it's called taking "long position" http://www.investopedia.com/terms/l/long.asp That's it, you don't bother about short-term profits, but looking at long-term results. If somebody "monopolize" market in 3rd world country.. when they're poor.. Ignoring that this market is giving little or none return at the moment, could win in the future, when they will get richer. Since the beginning of this thread we had too little data, to guarantee useful help in his case.. Starting from whether his colleague joked or not joked. (He should search for plans of his school. Timetables. They mention which class is used in what purpose). If he is really bothered, he should take Geiger counter and go to his old university room and see what device will show..

If volcano is causing radioactive isotope (nuclear isomer?) to be useless after flight from Spain, through Atlantic to USA, the same can be said about any flight to South America. Then I suppose so the entire South America also is rejected from usage of this diagnostic-radioisotope? If US don't make it, then 3rd world countries even more less likely.. ? You're looking at this from money point of view, while I am looking at this from helping ill people point of view. Don't South Americans need it?

No. Europe producer will be still producing for customers in Europe. And US branch of their company will be producing for customers in America. To not have lost during intercontinental flights. You thought about shutting down Europe producer, after opening US branch.. ?

Should not they rethink their business model, and start producing it near North America.. ?

Studiot, you gave me idea to reverse experiment. As a yet another variation. Instead of having laser on the ground and reading spot location on the boat. It's possible to mount steadily laser on the boat, and have large target (with grid of course) on the ground. And camera recording where is spot. It will be jumping back and forth as boat swimming on the waves. Certainly easier to have 10m height target on the ground, than swimming with 5m height target on the boat. Additionally catamaran could be used to even further reduce influence of waves and winds.

I watched the all 27 minutes of the video yesterday. And honestly must say, you spend the more time flying helicopter and playing volleyball than thinking and preparing for gathering data during the experiment. From your's precalculations of globe curvature there is visible that from 1.25m it will go to 4.32m, and what size of "target" you were using?! That's has barely 2m width and 1m height. It makes completely no sense to me at all.. ?! (If I would be expecting melting some metal at 1000 C, would I use container that has melting temperature at 200 C?) Additionally target was mounted at angle. IMHO you should mount it as perpendicular to the ground of boat as possible using spirit level.. If you would be seriously going to take this experiment, you should print grid on paper with 1 cm x 1 cm spacing, with some 10cm x 10 cm with slightly different background color (and/or chessboard), with printed numbers on side. With size 2m width, and 5m height. To be able catch the all laser positions on it. Mount it steadily to the boat using spirit level to be sure angles. Mount steadily camera (better 4K,60 FPS+) in the front of target, and filming it all the time, without breaks, and as fast as possible, to have weather influence as small as possible. (target, boat and recording camera should be each other not moveable during the entire experiment) Captain should be controlling boat looking at laser spot, and trying to keep it in the center of target. Don't do sharp movements. Reading results do in hotel room, looking at where is spot on target with grid, on the video recorded by camera. Nobody serious is doing measurements in the middle of experiment, instead store data by electronics devices. (The guy using tape measure, I could not believe my eyes.. completely unprepared people for experiment.. you looked like the first time in life doing physical experiment) And obviously REPEAT it several times. Additionally this "flat earth" mentioned everywhere in the video. It will obviously put you in "crackpot zone" if you will be going to discuss experiment with other scientists. I suppose so it's just there to catch attention to YouTube video, to earn money on advertisements from Google. Scientists seeking for the truth don't behave like that. At least should not. You didn't confirm that Earth is flat, but that photons from laser flied curved trajectory, at most. And identify source causing bending of the beam. Flat Earth + photons going straight line will have the same (or similar) results as curved globe Earth + photons going curved path. And obviously REPEAT it several times. With different conditions, with different time of day, and different time of year..

Questions to OP of this thread. I just clicked link (have not watched it, 30 mins!), and wow, there is "Flat Earth | Laser Test Proves The Flat Earth" title.. Is it serious? Literally.. ? If you're taking it literally, as flat Earth like in middle ages, then why don't you build rocket like these guys: It reached 30 km.. 3 times as high as commercial airplanes. And 7%-9% of altitude of ISS space station (330-410 km) How about making your own Hydrogen filled balloon, with GPS and couple cameras recording flight.. ? If Earth is flat, how curved shadow on the Moon appears? Earth is blocking photons traveling from the Sun..

Couple things to reconsider: - Earth has no constant radius, 6371000 m is average. For a start you could calculate varying radius using GPS latitude. See "Location-dependent radii" section https://en.wikipedia.org/wiki/Earth_radius - Because of slightly non-spherical shape of planet, pointing laser north-south line, won't have the same result as east-west. - Lake Balaton surface elevation is 104.8 m.

I was using LightWave 3D. Not free for ordinary user. Although I received it for free. If we select two points and use Detail > Measure > Measure Points, it's calculating length of line, x,y,z abs delta between points.

I made SpreadSheet how results changes with various length line from center of table to "middle" of left/right side (A). Here is zoomed in range where it's starting growing: (25 row is the smallest) A is auto-incremented. 1-A is rest. B=SQRT((1-A)^2+0.5^2) Total length 4*B+2*A+1

Angle 120 degrees. Total length approximately 4.73.

Where? Because I don't see.. Or don't understand what do you mean.. Human made metallic Hydrogen has density 0.6 g/cm3, you mentioned 100 times higher density 60 g/cm3.. If somebody would mention water with 100 g/cm3, everybody would know that it's no more water, rather Hydrogen and Oxygen plasma.. Core of the Sun has density 150 g/cm3, and in such plasma there are fusion reactions.. Your's 60 g/cm3 is 40% from density of plasma in the Sun's core.. Near the core of the Sun there is 40 g/cm3 according to https://en.wikipedia.org/wiki/Solar_core

According to https://en.wikipedia.org/wiki/Metallic_hydrogen "In March 1996, a group of scientists at Lawrence Livermore National Laboratory reported that they had serendipitously produced, for about a microsecond at temperatures of thousands of kelvins, pressures of over a million atmospheres (>100 GPa) and density of approximately 0.6 g/cm3,[16] the first identifiably metallic hydrogen.[17]" Where did you find 60 g/cm^3, if I may ask.. ?

Here you go: [math]\gamma + 1.022 MeV \rightarrow e^- + e^+[/math] [math]\gamma + 1.876544 MeV \rightarrow p^+ + p^-[/math] Pair production of matter and antimatter, electron and positron, proton and antiproton. https://en.wikipedia.org/wiki/Pair_production

HTML, AJAX, MySQL are not computer languages. Albeit it's worth to learn them. ps. You forgot Java. My list in priorities to learn: C/C++,Java,PHP,JavaScript.

You look at star, focus optics on it, and measure its properties like intensity. Repeat it over and over again at various days of year (especially +90, +180, +270 days later) This way astronomer can calculate parallax. https://en.wikipedia.org/wiki/Stellar_parallax and calculate distance to a star in close area. Once you have distance, once you know intensity, various other things about star can be calculated. Reverse inverse-square law, and you have initial power of star, and its temperature. Composition can be estimated by analyze of spectral lines. If it's wobbling, it could mean there is 2nd star, or planet(s). If it's periodically blinking (decrease of intensity), it could mean there is planet (or couple of them) obscuring surface of star. etc. etc. While watching area where there is nothing in weaker telescope, after even minutes, days or months of watching that area, the more and more photons from that region arrives, and after computer analyze new object can be identified. You can't look at star, and expecting you will see what is behind that star (except situation as in gravitational lensing). But at various days of year, star is obscuring slightly different region of sky behind it. d=c*t so t=d/c where d is distance to object in meters, t is time spend on flying in seconds, c is speed of light 299792458 m/s Distance d is calculated using parallax or other method.

Ideal point light source, is emitting photons in the all directions, and obeying inverse-square law: [math]P=\frac{P_0}{4\pi r^2}[/math] P0 is initial power of star, in Watts = Joules per second. P is power per area unit here on the Earth, in Watts per meter square = Joules per meter square per second. https://en.wikipedia.org/wiki/Inverse-square_law So, the larger area of device, the more photons can be reflected/refracted by lens, and then absorbed. Star that burned entirely from our point of view is invisible. It can still be seen burning, from other galaxy "behind us", because "final" photons didn't arrive there yet. But they will see much smaller quantity of photons per their area unit. Star that is invisible, it's invisible in 400nm- 700nm visible photon spectrum range, it can still be seen in f.e. infra-red or radiowave spectrum range. It depends on temperature. Hot body sends higher energy photons. See black body radiation article. https://en.wikipedia.org/wiki/Black-body_radiation You can't see that tea/coffee is hot or cold. It's temperature is ~90-100 C (373.15 K). But if you would use infra-red camera, you would instantly see it as red-yellow-white colored on the display, significantly hotter than surrounding environment (f.e. 25 C). The hotter body, the more energetic photons emitted.

Do you heard about lizard regenerating their tails? https://en.wikipedia.org/wiki/Lizard "Many lizard species (including geckos, skinks, and others) are capable of shedding part of their tails through a process called autotomy. This is an example of the pars pro toto principle, sacrificing "a part for the whole", and is employed by lizards to allow them to escape when captured by the tail by a predator. The detached tail writhes and wiggles, creating a deceptive sense of continued struggle, distracting the predator's attention from the fleeing prey animal. The lizard will partially regenerate its tail over a period of weeks. A 2014 research identified 326 genes involved in the regeneration of lizard tails.[8] The new section will contain cartilage rather than bone, and the skin may be distinctly discolored compared to the rest of the body."

That applies to almost the all users making threads in Speculation forum... So maybe some native English speaker would make thread and pin it "What scientific theory does mean".. etc. How to make measurements.. how to verify equations are correct during experiments, etc.

You have sci-fi movie vision of what "dimension" is.. "the dimension of a mathematical space (or object) is informally defined as the minimum number of coordinates needed to specify any point within it" https://en.wikipedia.org/wiki/Dimension Chess analogy: Say you have chessboard, there are 2 dimensions with 1st dimension 1,2,3,4,5,6,7,8 and 2nd dimension A,B,C,D,E,F,G,H possible coordinates. If one would add yet another dimension to chessboard, figures could move up and down. f.e. a,b,c,d,e,f,g,h possible values. Figure at A1a would not beat/overlap figure at A1b. With 2 dimensions A1 overlap A1 (without a and b in 3rd dimension).

Nonsense. You forgot to mention the one important rule in your game.. The way you described above, one could join 1-4,2-5,3-6 (or 1-4,5-2,3-6). And have 3 total length. But there are missing 4-5 and 2-3! Therefor the way you explained game in #1 post, the correct answer is 5.

Noble gases are not chemically reactive. Difficulty in going them into reaction explains why the first noble gas compound was found just in 1962. https://en.wikipedia.org/wiki/Noble_gas_compound Half-life of the most stable Radon isotope is just 3.8235(3) days. https://en.wikipedia.org/wiki/Isotopes_of_radon

Isn't (x+y)/(x-y)*(x-y)/(x+y) equal to LaTeX: [math]\frac{x+y}{x-y}*\frac{x-y}{x+y}[/math] ?? Maybe some parenthesis missing somewhere? Which is equal to: [math]\frac{x+y}{x+y}*\frac{x-y}{x-y}[/math] [math]1*1[/math] [math]1[/math] (as long as no division by 0) f.e. if I make OpenOffice SpreadSheet with A1=1000 B1=500 and C1=(A1+B1)/(A1-B1)*(A1-B1)/(A1+B1) Result is 1. If I make A1=B1=1000 f.e. OpenOffice complains there is division by 0. They will be z'=1/z or z'=z-1

Edible dormice: High food availability slows down cell aging http://www.vetmeduni.ac.at/en/infoservice/presseinformation/presseinformationen-2016/edible-dormice-high-food-availability-slows-down-cell-aging/ This is worth reading and rechecking by other researchers, and with different kind animals. More scientific paper http://jeb.biologists.org/content/219/16/2469 Best Regards!