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Everything posted by Sensei
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How can different types of plastic be cheaply and easily identified?
Sensei replied to Johnish's topic in Organic Chemistry
Bail for all plastic and glass containers would solve all issues straight away.. Company that produced something would receive them back. Majority of glass containers (99.9% of beer) are here with bail ($0.1) It's pity it's not extended to the all containers. They just need easy way to get ride of paper label, and glue used to attach it. Different types of plastics have different densities: http://www.dotmar.com.au/density.html So by measuring mass, and volume, you can calculate density and more or less precisely identify used plastic. As long as it's clean (no labels, no attached things), and measuring device is precise.. Plastics that have smaller density than 1 cm^3 (density of water) will float in water. So to find out Polyethylene/Polypropylene you just need to blend plastic and let it float and sink in water. -
Kramer on energy (hijacked from "What exactly is energy?")
Sensei replied to Kramer's topic in Speculations
He is searching for unified theory, that doesn't explain everything as excitations on fields. That brings us back to the main question of this thread - what is energy, and what is mass. Photons produced during annihilation of electron, and its antiparticle, positron have positive energy, so the same mass of electron and positron is positive value. Dirac was mistaken. There is no need to exists negative mass to cancel positive mass. Energy-mass is equal on both sides of equation.. e+ + e- -> y + y in terms of energy can be written: me*c^2 + me*c^2 = h*fC + h*fC fC - Compton Frequency = 1.23559*10^20 Hz Compton Wavelength = c/fc = 299792458 / 1.23559*10^20 = 2.42*10^-12 m = 2.42 pm. in terms of charge: +1e - 1e = 0e + 0e Suppose so we have electron and positron in black-box (or billions of them), that is put on precise weight, They have total mass 2*me before annihilation. After annihilation weight will not measure any change of total mass. Photons will be created, absorbed, another 2nd created, absorbed and so on. Mass won't change at all. We don't know that they annihilated or not - it's inside of black-box. Earth's core and internal have a lot of radioactive isotopes that decay, mass changes to energy (see mine signature to learn how to calculate it), For alpha, proton and neutron decay, that doesn't make Earth decreasing mass in time. As long as no neutrino is emitted to outer space. -
Where have you been whole XX century when we were working on quantum physics.. ? Molecules flowing in circle, will be of course colliding with them self, but also with pipe or container (in your case nano tubes), and giving part of their kinetic energy to particles of wall. Which will result in increase of temperature of pipes/container. If you would manage to make device that's absorbing energy from environment, and it would not ever release that energy back to environment, device would melt after some time. There is not much energy in environment that you can get this way. 1 m^3 of air at RT has approximately just 2.7*10^25 molecules. After decreasing their temperature for 1 C, you could get just 373 J energy (1.38*10^-23 J per single molecule per 1 C). ps. Collisions between particles are elastic and inelastic.
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Yes, I know. That is why I was asking him to clarify his statement....
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Do you mean that ANY photon has random polarization during emission (regardless of entanglement).. ?
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Average visible photon has wavelength ~532 nm so energy of such photon is h*c/wavelength = 6.62607e-34 * 299792458 / 532e-9 = 3.73e-019 J Sun is emitting at Zenith 1360 J/s of energy per m^2 of Earth (including absorbed by atmosphere). (I am simplifying calcs to not take care of UV/IR/MW - let's hypothetically assume the all is from visible spectrum) 1360 J / 3.73e-019 J = ~ 3.65*10^21 photons per m^2 per second. Knowing above, you can calculate how many photons is in volume of sphere with radius equal to distance between Sun and Earth (or any further if you want).. You should learn about inverse square law, to calculate energy per area unit. In other thread I posted mine animation showing inverse square law for a few particles spreading in the all directions from one origin.
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It cannot. I suggest buying equipment and checking by yourself.. Lasers, polarization filters, beam splitters etc. are quite cheap. http://en.wikipedia.org/wiki/Photon_entanglement
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Does Light Travels In a Straight Line?
Sensei replied to Nicholas Kang's topic in Modern and Theoretical Physics
Search google for: snell's law diffraction single and double slit experiment you might also being interested about polarization filters. These things are cheap to buy in shop with physics equipment. Do experiments with lasers, and mirrors. -
Image not (hard to get image of particle at rest), but whole electrostatics is about measuring charges coming from electrons at rest that repel each other.. http://www.sparkmuseum.com/STATIC_MISC.HTM Wimshurst machine http://en.wikipedia.org/wiki/Wimshurst_machine Electroscope http://en.wikipedia.org/wiki/Electroscope Don't you have these devices.. ??
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Electromagnetic radiation and steady state of hydrogen atom
Sensei replied to Jeremy0922's topic in Speculations
See thread http://www.scienceforums.net/topic/84357-how-to-calculate-planck-const-at-home/ post #5 and #26 how you can calculate Planck const from just a few electronic elements and voltmeter, ampere meter etc. -
"how to calculate Planck const at home"
Sensei replied to Iwonderaboutthings's topic in Quantum Theory
Maybe he will find peace now in his heart.. He appeared more and more pissed off. Perhaps we were giving him too much data.. -
"how to calculate Planck const at home"
Sensei replied to Iwonderaboutthings's topic in Quantum Theory
See section "Colors and materials" in article http://en.wikipedia.org/wiki/Light-emitting_diode There is table with data how drop of voltage on element is related to wavelength and color of photon emitted by LED. ps. Iwonderaboutthings had already trouble understanding all these informations, without going into such details. -
Actually, in coil electrons don't move in circle, but in spiral. Single electron is just once passing through wire. When electrons flow in one direction in coil of course it will produce magnetic field, that anybody with "compass array" device can see on his own eyes. But if we will use alternating current, electrons flow once in one direction, once in opposite direction. Can you detect magnetic field when frequency of AC would be counted in millions or billions Hz? What does show "compass array" device, if you will place it close to coil through which there is flowing low frequency AC, or high frequency AC.. ? What does show "compass array" device, if you will place it close to discharge tube with Hydrogen and turn high voltage on to ionize it.. ? The issue I see here is that spectral lines are obtained from discharge tube, with ionized plasma. But electric neutral Hydrogen gas is not mixture of proton and electron, but H2 molecule, two protons and two electrons. ps. Where in USA and UK somebody can buy "compass array" like below one? I searched couple times on Google and can't find anything.. Here it costs $40 in the regular shop. Whenever somebody asks on physics forum about "moving electron in circle around proton" I know they don't mean it literally. Circle is 2d figure, with missing one axis to 3d. Analyze should be done using the all 3 dimensions. What are your predictions of magnetic field lines around it for such "coil".. ? Imagine it's single long wire.
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Electromagnetic radiation and steady state of hydrogen atom
Sensei replied to Jeremy0922's topic in Speculations
You turned mine answer upside down... -
Electromagnetic radiation and steady state of hydrogen atom
Sensei replied to Jeremy0922's topic in Speculations
It would violate conservation of energy, if electron would forever emit photons. It would means that electron has infinite amount of energy (which is obviously not true). -
"how to calculate Planck const at home"
Sensei replied to Iwonderaboutthings's topic in Quantum Theory
That depends on what you do. I am using e as elementary charge everyday, to go from Joules to eV unit and reverse.. e as Euler number is used while calculating decay rate using mean-life, f.e. -
I believe they should be mandatory to teach life skills in school
Sensei replied to Marshalscienceguy's topic in Politics
I was watching tv document about some South Indian tribe. One guy was complaining that now their children are going to school and teaching nothing useful. Complained about learning counting, learning letters and how to read ("where is bookstore in jungle?") He said that when he was young his father taught him how to fish, how to hunt, build house from wood and leafs.. Now his kids don't know how to survive in jungle.. -
Do you feel heat on face when going outside in sunny day or while sunbathing.. ? That are billions of billions photons per second hitting your body, and increasing temperature of your atoms.. Increase of temperature is detected by nerve cells and informing brain about it. Put hand to strong laser > 1 W, and it will burn your body - large quantity of photons per small area unit per second will heat your body, and brain will be informed about damage, causing alarm, and reaction "run away". Continuous spectrum = infinite energy = black body/ultraviolet catastrophe.. http://en.wikipedia.org/wiki/Ultraviolet_catastrophe Average visible photon has wavelength ~532 nm so energy of such photon is h*c/wavelength = 6.62607e-34 * 299792458 / 532e-9 = 3.73e-019 J Sun is emitting at Zenith 1050 J/s of energy per m^2 (at least such amount is reaching ground at max). (I am simplifying calcs to not take care of UV/IR/MW - let's hypothetically assume the all is from visible spectrum) 1050 J / 3.73e-019 J = ~ 2.8e+21 photons per m^2 per second. That's average 2812 photons per 1 nm^2 per second of your face. More photons per area unit per second = more total energy = solid materials are melting, liquids are turning to gas, and in extreme situation gas is ionized (f.e. explosion of nuclear weapon, creates plasma inside). (and it can be used to cutting metals or other materials in laser cutting machines ) Some of these photons are absorbed, some are reflected (therefore other people can see you in day light), others are refracted. If your cloth is black, you feel hot, black surface is good visible photons absorber. while wearing white cloth, you feel better at summer, visible photons are reflected.
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It must be language barrier.. For me "work like radio receiver", is not the same as "work as radio receiver". "Because the underlying physics are the same... electromagnetic fields, for both sunlight" Sunlight is visible light. The "problem" with "working solar panel like radio receiver" (but for visible spectrum) is such that we WANT to get energy from photons with as wide as possible range. Limiting to just f.e. 650 nm +-10 nm would decrease output power from such device.. Radio receiver is receiving at wide range of wavelength - but it's electronics inside fine tunning to specific frequency (they overlap with all others).
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Solar experiment that gets 7KW per square meter of sunlight??
Sensei replied to SolarGraphene's topic in Experiments
But solar panels generate electricity. Your setup is just heating water. For now you can use it to make a cup of tea or coffee in 6 minutes or so. -
Enthalpy, please reread his comment (post #20).. He didn't want solar panels to work with radiowaves frequencies..
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A general discussion on the relationship between Photons and Time.
Sensei replied to Alias Moniker's topic in Speculations
That depends on how to interpret passing through transparent medium with refractive index > 1.0.. If you will use beam splitter, one laser beam pass through air/vacuum, other one through container with f.e. water or other transparent fluid. Photons from the second one will arrive later.. -
A general discussion on the relationship between Photons and Time.
Sensei replied to Alias Moniker's topic in Speculations
Lorentz transformation is designed for particles that have rest mass.. This message went through fiber wire on the bottom of ocean, with speed of light... You can take fiber wires with lengths 1 km, 10 km, 100 km, and emit light to them from the same source, and calculate delay on other end of fiber wire. You can send photons to satellite far away in cosmos, and measure delay of reply. And it'll be t=2*distance/c