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Sensei

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Everything posted by Sensei

  1. We can distill water to get pure H2O without minerals and other unwanted substances. But after pumping to the ground even pure H2O there is chance (close to 100%) that it'll be contaminated inside of Earth. During travel back to sea level molecules that was flushed by water/vapor will start gathering on installation.
  2. http://en.wikipedia.org/wiki/Geothermal_gradient Temperature increases ~25 C for each 1 km of depth average on Earth. Which gives 4 km average to reach 100 C. We need 100 C to heat water to become vapor. But it's not constant! Different locations will have different depths at which we will find enough temperature. Drilling 2-3 km well cost ~2 million dollars (at least for gas and oil), hydraulic fracturing is 0.5-1 mln usd. If you are thinking about it seriously you should start from making cheap drilling..
  3. NaCl dissolved in H2O is in reality ions Na+ and Cl-. They are spread evenly across of whole water, so we can say that distances between ions are pretty much equal (none part of water has higher concentration). From quantum physics point of view Sodium is giving away its electron (because it wants to have 2,8 electrons in shells, instead of 2,8,1), and Chlorine is taking electron (because it wants to have 2,8,8 electrons, instead of 2,8,7).
  4. Theory must be consistent with experimental data, not reverse. If you will send blue light and red light from lasers, they will reach detector at the same moment. So regardless of photon energy, frequency and wavelength, they must have the same velocity. Other example - if you have 3 km long fiber wire, and you will send data at frequency f0 and f1, you will receive data at the same moment 10 microseconds later. If their velocity would be different data would be desynchronized.
  5. Galileo had no idea about vacuum. He lived in 1564-1642. The first gas was discovered in 1766 (Hydrogen), 1772 (Nitrogen), 1773 (Oxygen), 1774 (Chlorine). The main question: I guess so repeatable every time..
  6. Mine code is for loop 5 times, not 3. And text displayed to user is different. fSum instead of aSum as name.
  7. To create just Hydrogen and Oxygen you need to use right material for electrodes. http://en.wikipedia.org/wiki/Electrolysis_of_water On picture on the right there are used pencils. That's no joke. Graphite is very good for this kind of job. But it's hard to find really pure one in the shops (at least here).. I went to the shop with multimeter and checked the all they gave me to make sure they're passing current (~75% did not work). If you will use metal such as f.e. Aluminum on one electrode there will be created Hydrogen with normal volume, but on second one much less than expected volume of Oxygen (1/8 volume of that of Hydrogen) - the rest of Oxygen will join with Aluminum and produce Al2O3 (I have couple liters of it at home exactly from electrolysis..) part/all of Aluminum electrode will literally disappear. One hour of electrolysis with 230 VDC (using silicon bridge rectifier KBPC-610 6A/1000V that cost 0.5$) is enough for wiping out entire electrode made of 0.5mm Aluminum plate. With such setup you can create 25 ml (single test tube) of Hydrogen in 91 seconds, and nearly 1 Liter in 1 hour. Different metals will produce different substances. You will see it immediately as f.e. some colorful substances in water making it opaque for a while. After leaving them alone f.e. for night or longer they will sink to bottom of container. For instance steel electrodes are producing red-yellow water, and absolute no Oxygen in test tube, so entire Oxygen is reacting with Iron.. And again - this can be used to measure masses of either Oxygen and metals. Measure mass of metal electrode prior electrolysis and after electrolysis (when part of it literally disappeared - it's now dissolved in water). After getting rid of water from container, there will remain just metal oxide, and you can measure its mass..
  8. Two waves.... ? I have 2 usd cheap laser at hand that has 5 mW max output, and wavelength 650 nm. 1 W = 1 J/s so 5 mW = 5 mJ/s = 0.005 J/s Photon with wavelength 650 nm has: E=h*c/650 nm = 6.62607*10^-34 * 299792458 / 650 *10^-9 = ~3.056*10^-19 J energy... Assuming (unreal) that there is no lost and all energy is converted to photons with such wavelength, this mine tiny laser will produce 0.005 J / 3.056*10^-19 J = 16,360,879,214,888,979 photons emitted per 1 second of work.. That's 16,360,879 per nano second. When such tremendous quantity of photons will collide with atoms in wall we see dot. From the all directions we look at it. Photons are reflected in the all directions
  9. Ep = m*a*h Distances traveled by object with acceleration a is: h=1/2*a*t^2 so m * a * 1/2*a*t^2 = 1/2*m*a^2*t^2 kg * m^2/s^4 * s^2 = kg * m^2/s^2 = kg * (m/s)^2 And we are receiving other equation back. Ek= 1/2 *m * v^2
  10. Then your teacher is incompetent.. Because it's in flagrant conflict with this "(Hint: use pass by reference)"... In ANSI C, you have to replace references by pointers. #include <stdio.h> void getNumSum( float *aSum ) { float data = 0.0; printf("Please input a float number: "); scanf("%f", &data ); *aSum += data; } void main() { float aSum = 0.0; for( int i = 0; i < 5; i++ ) { getNumSum( &aSum ); printf( "Sum %f\n", aSum ); } }
  11. References are in cpp, not in old c. Rename file and should be fine.
  12. You named file .c but it's .cpp code
  13. It's not exactly what I posted in #4. Compare lines one by one..
  14. Can't you simply copy and paste to compiler what I wrote in post #4? This time I have compiled above code, and tested and worked as intended...
  15. Photon with initial frequency f0 should decay to two (or more) photons with frequencies f1 and f2, which are sum: f0 = f1 + f2 (energy must be conserved) So we actually see decay of photons in entire Universe all the time when photon is absorbed by matter and new photons are emitted at longer wavelengths.. Fluorescence is example of this process. High energy UV light is absorbed, lower energy visible light is emitted. But it's induced decay. By medium that's on photon path. But how can you be sure whether photon emitted by galaxy f.e. 10 bln light years from us wasn't absorbed and emitted by some material between galaxies.. ? Spontaneous decay the most likely won't be distinguishable from induced decay by interaction with medium..
  16. Rather something like this: #include <stdio.h> void getNumSum( float &aSum ) // do you see difference here?? Parameter must be with & { float data = 0.0; printf("Please input a float number: "); scanf("%f", &data ); aSum += data; } void main() { float aSum = 0.0; for( int i = 0; i < 5; i++ ) { getNumSum( aSum ); printf( "Sum %f\n", aSum ); } }
  17. void getNumSum( float &aSum ) { float data = 0.0; // ask user for float here... aSum += data; }
  18. What random numbers you are talking about?! If you'll measure your mass to be f.e. 78 kg it means that you are made of: mass of proton/neutron is approximately 1 g/Na= 1 g/6.022141*10^23 = 1.66 * 10^-24 g ... 1.67 * 10^-24 g (different element have different mass of protons and neutrons f.e. Carbon-12 has mass=12 g/Na, but Hydrogen has mass 1.0078 g/Na) 78 kg = 78000 g 78000 g / 1.67 * 10^-24 g = ~4.67 * 10^28 protons and neutrons approximately in 78 kg body.. How can we calculate mass of Hydrogen and Oxygen? While electrolysis.. We are filling box with well known mass and volume of water. Then start electrolysis. In one test tube there is collected Hydrogen and in other test tube is collected Oxygen. We can measure volume of Hydrogen, volume of Oxygen, mass and volume of rest of water in box.. Using Hydrogen and Oxygen as product to create other substances we can gain knowledge about molar masses of the all elements.. And you can do it in couple minutes at home.
  19. It's easier to see process with animals than vegetables. Imagine that we have bears that have childes. Parents can have whatever colors. Childes have: one white, one gray, one black (natural mutations). If they would be living in forest, white one would be easily visible by preys, and couldn't survive and spread its genes to the next generation. If they would be living in arctics, white one would be the hardest visible, unlike gray and black one, which wouldn't survive, starving. White one would spread genes. Species with wrong color in environment are not surviving. Predators can't be easily visible to preys. And preys can't be easily visible to predators. Pigeons owners are using this knowledge to create white only pigeons. Even if original parents have natural colors. But instead of predators they are choosing which color birds should survive. Vegetables more often fight against eating by animals by creating toxics substances. Or by making fruits good to eat, so other part of vegetables are leaved intact by animals.
  20. The simplest fusion is process of joining two protons together: p+ + p+ -> D+ + e+ + Ve In order it to happen, there is needed to overcome natural electrostatic repelling of two equal charges. Do you understand now why they have to be accelerated? Hot particle = fast particle. Cold particle = slow particle. This can be rewritten using quarks: uud + uud -> uud + udd + e+ + Ve At least one of up quarks must have enough kinetic energy, or receive from external source, to be converted to down quark which according to quark model has higher mass than up quark. Newly created neutron is joining with proton forming Deuterium. p+ + n0 -> D+ uud + udd -> ududud
  21. Try something like: for( j = 1; j <= x; j++ ) { for( i = x; i >= 1; i-- ) { if( i > j ) { // print star } else { // print i } } }
  22. Sensei

    Chemistry

    Which triprotic acids did you have at school?
  23. I posted it to inspire people to experiments. Everything should be created, checked and published. For dead rats and small animals these things are not negligible and worth ignoring. Replacing H by D, is just an example. H2O has 18u HDO has 19u (+5.5%) D2O has 20u (+11%) Some might say it's small change in mass.. (apparently not small for dead rats) CH4 has 16u CD4 has 20u (+25%) Is it still small and not worth experiments showing what properties will have Methane with Deuterium? C2H5OH has 46u C2D5OD has 52u (+13%) How other substances will behave after putting them to Deuterium Ethanol? Will they be soluble (or not) at the same as with normal Ethanol? etc. kind of questions can be asked. How will behave polyethylene/polypropylene which has only Deuterium? Will it bend or crack at the same moments as regular one? Without creating these substances and careful examination how they behave we can't judge with 100% certainty how they behave.
  24. Hello! Heavy water according to wikipedia is causing death of rats in a week of drinking. http://en.wikipedia.org/wiki/Heavy_water The only difference from water is replacement of Hydrogen element by Deuterium, D2O or HDO. Just because of extra neutrons properties such as boiling point, and melting point are slightly different (not to mention other hidden properties hard to measure). D2O (Heavy water) Freezing point (°C) 3.82 Boiling point (°C) 101.4 HDO (Semiheavy water) Freezing point (°C) 0.0 Boiling point (°C) 100.7 H2O (Light water) Freezing point (°C) 0.0 Boiling point (°C) 100.0 This example shows that it's important to examine the all chemical substances with careful counting their neutrons as standard procedure. Produce isotope pure element, then mix them with other isotope pure element, receiving mixture with well known neutron quantity, and use it instead in tests. Hydrogen chloride acid can have more than 6 versions (4 stable): H-Cl-35 H-Cl-37 D-Cl-35 D-Cl-37 T-Cl-35 T-Cl-37 Their properties should be slightly different. Also result of their reactions with other substances should be slightly different. Precise experiments should show how much. Taking proper care of neutrons should open door for finding old-new materials, with different parameters (starting from different boiling, melting points). f.e. plastics with Deuterium instead of Hydrogen in chains.
  25. Hello! Do you know some application for generating chemical formulas? I mean something like- enter quantities of atoms, and program should show the all *) existing and plausible chemical formulas possible to make from them. f.e. If I enter C=1,O=2, it will show CO2 (O=C=O), If I enter C=3,H=8,O=1, it will show CH3-HCOH-CH3 but also C3H7OH *) in reasonable amount..
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