tomek888

Yes you are right, now I read my post and the second task was not clear. So thank you very much for help - About the first one, I can assume that if I place the hotter fluid below the colder, they will mix faster and then reach equilibrium faster than the other scenario with colder fluid below hotter?

But I think that in the second one it's not important how did I heated these rods - the question is that you have both rods heated to the equal temperature and you are waiting for them to cool down - and which one is going to be first. And the first one - you mean that when you open the valve and in the upper container you have hotter fluid it will stay there ?

My friend ask me these as 'what if..' and here I am looking for help. 1) When you open the valve the upper fluid will 'flush' in to the lower container - they are the same weight. 2) No more data provided on this one - lets say both were heated to 200° F and which one will reach 90° F first

Hello, Can you guys help me with these two tasks : 1. I have two containers one above the other. In the first one, the fluid temperature is greater then the second one (let's say T1>T2).Containers have a valve between them, when you open it, fluids will mix. In which configuration mixed fluid will reach its equlibrium faster - if T1 is in the upper container or if T2 is in the upper container ? Or it does not matter? 2. I have two rods that are the same material, same length but different diameter, one much larger then the other. Both are heated to lets say T1. Which one will first get to T2 (lower than T1) ? I know its basic, but I will appreciate any help with those Thank you in advance