-
Posts
10078 -
Joined
-
Last visited
-
Days Won
37
Mordred's Achievements
SuperNerd (12/13)
1.6k
Reputation
Single Status Update
-
Do you like it? Do you think this geodesic equation is simple enough to be possibly right?
[math]\nabla_n \dot{\gamma}(t) = \nabla_n\frac{dx^{\mu}}{d\tau} \equiv\ min\ \sqrt{<\dot{\psi}|[\nabla_j,\nabla_j]|\dot{\psi}>} = 0[/math]
-
I hold that the RHS must [always] equal zero because the curve component is squared, meaning by definition that the covariant derivatives have to be the same. I defined the time derivative early on with a j-subscript. This necessary application fundamentally implements that the geodesic always equals zero. The fact the connections are acting classically could also be a hint for classical gravity at the quantum scale? Certainly, Penrose has suggested classical gravity in the phase space.
-