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When synthesising brombenzene by reacting benzene with bromine and ferric turnings as a catalyst one gets not only the desired bromobenzene, but also di- and trisubstituted products. Now, since bromine is deactivating substituent, but still directs further substituents to ortho and para positions, what would be the structure of these sideproducts? Dibromobenene could either be 1,2 or 1,4, but what about tribromobenze?

I'm supposed to determine products for the given set of reactions (A,B, C) CH2=CH-CH3 + HBr --> A A + H2S --> B B + CH3I --> C A is obviously 2-bromopropane, but what I'm unsure about is whether it will react with H2S in both substitution and elimination? If yes, would the resulting alkene (elimination product) react with CH3-I to form alkyl halide, whereas thiol (substitution product) would react to form sulfide?

Yes, that's it Thank you

In my organic lab an assistant showed us a sort of tiny flask used for distilling small amounts of organic solvents and I can't remember what it's called, it's got a rounded bottom and an annular convexity above in which the vapors condense... Anyone knows what I'm talking about?

*Cl + CH4 -> HCl + *CH3 *CH3 + Cl2 -> CH3Cl + *Cl CH3Cl + *Cl -> HCl + *CH2Cl *CH2Cl + Cl2 -> CH2Cl2 + *Cl The reactions should go on like this to form the other two methyl chlorides, until all of the Cl2 is used up. Also, methyl radicals should react to form ethan: *CH3 + *CH3 -> C2H6 If I got it right, 4 Cl2 molecules will give you one molecule of each methyl chloride.

From what I know, you need light in order to gain radicals, so all of the reactions should proceed in light. Also, it is difficult to add halogens to aromatics because the resulting compounds are unstable, maybe that's why you need more radicals (more light) to get benzene, toluene and t-butyl benzene going... Just a guess, though

I know about the fingerprint region, I wasn't sure whether those peaks are actually in it, though (since those are ~14500 and 1500). Thank you!

Hi everyone, I'm analyzing these IR spectra and there are few things I'm uncertain about... 1-phenylethanol: I can't make out what are the two peaks at 14500 and 1500? cyclohexanon: how to determine which of the two peaks (2938 or 2863) is due to C-H vibrations? or it's both of them? benzoic acid: is there a way to determine which of the peaks ranging form 2560 to 3072 are due to OH vibrations, and which are due to aromatic ring CH stretching? ps sorry about the poor quality of the images

I think I see the point now, thank you guys. Just one more question, I give preference to the chlorine substituents based on the alphabetical order, not because of the atomic mass?

But the sum in 2,4-dichloro-5-methylhexane is 11, whereas in 3,5-dichloro-2-methylhexane it is 10...?

I thought this simple haloalkane was supposed to be 3,5-dichloro-2-methylhexane, but my professor said it was 2,4-dichloro-5-methylhexane, (alphabetical ordering?) How come, shouldn't I simply assign the smallest possible numbers to alll of the supstituents?