If 1.20 grams of salicylic acid is reacted with excess methanol, what mass of ester should you expect to achieve theoretically? Molar masses of.. salicylic acid is 138.13g/mol methanol is 32.05g/mol ester (methyl salicylate) is 152.16g/mol Mole ratio 1:1 My work: 1. 1.20 g salicylic acid (1 mol salicylic acid/138.13 g salicylic acid) = 0.008687468 mol salicylic acid 2. 0.008687468 mol salicylic acid (1 mol ester/1 mol salicylic acid) = 0.008687468 mol ester 3. 0.008687468 mol ester (152.16 g ester/1 mol ester) = 1.32 g ester so 1.32g of ester would be expected. Is my work correct? or do I have to use the excess reagent to find the mass of the product?
