Beans06

Okay so far I get it. what I don't get is what do I do with the z because by substituting I got : 4a-2b+z=0 16a+4b+z=0 9a+3b+z=-15

Okay can u please explain it in more detail? I kind of understand it but not fully

That's what I did y=a(x+2)(x-4) but it didnt give me that minimum of -27?

how do you find the minimum of a parabola that has the x- intercepts -2 and 4 and goes through the point (3,-15)? I don't get how to get the minimum if I don't have a starting equation to work with can someone please help me on this ?

That's what I was wondering if u could help me get the equation I don't get what I have to do next ? I know how to solve that equation x= 1 and y =2 I was wondering if you could help me understand how to get the minimum parabola with out having a equation to start with ? I know about a parabola but only when I have an equation then I can find the maximum or minimum but with out and equation it's hard to find that or I just don't understand how to find that .

No I never heard of that but those are the only points that the question gave me

How do u find the minimum parabla that has x-intercepts of -2 and 4 and passes through the point (3,-15) ? I have that the answer is -27 but I don't get how to get that answer can some please help ?