ANALYSIS
3. Determine the average [CH3COOH] in mol/L
I have no idea what this is asking for. The past two questions have made me determine the volume of NaOH at equivalence (22.5mL) and the concentration of CH3COOH (3.75mol/L).
All other information: Concentration of NaOH = 1.5mol/L, volume of CH3COOH = 20mL, initial volume of NaOH = 50mL, initial pH of CH3COOH = 2.4, final volume of NaOH trial 1 = 22.8mL, final volume of NaOH trial 2 = 22.2mL, pH of colour change trial 1= 8.7, pH of colour change trial 2 = 8.0.
