What is the limiting reactant when 31.3 g of manganese (II) chloride, 48.3 g of chlorine, and 25.7 g of water react to produce manganese (IV) oxide and how much hydrochloric acid is produced?
When I wrote the balanced equation I got MnCl2 + Cl2 + 2H2O = MnO2 + 4HCl
and when I attempted to find how much HCl was produced I came up with 104.2g... which is not an answer choice.
( 25.7*4*36.5/18*2 = 104.2)
Can someone check my math or tell me what I am doing wrong? I am also unsure how to go about finding the limiting reactant. This is a review for a final and I'm a little rusty.
Any help is appreciated. Thx
