in the formula T=2pi*root of L/g
there is nothing to effect it with out L and g
but as far as i know pendulam works in free place.but there is water here
but you are right that the upward byuiant force affects the g.because if the bob gets a force F=mg in free place ,in water it will get a force F-f(upward force)
A simple pendulum sinks in water. The density of water is 1000kgm-3. The density of the bob is 1500kgm-3. The effective length of the pendulum is 1m. Gravitational acceleration is 9.8ms-2. What is the period of the pendulum? Neglect viscosity.
i can measure the period in the air or free place.but how can i measure the friction of water?
there is a lamppost which is 40 m high.5 m infront of the post there is a metal plate which is 8 m long.
which angle of the plate with the verticle line will give the longest shadow?
r1 is the outer one.but if I want to find the moment of inertia I must have to use this two radios r1 and r2,isn't it?
if I do it,in the last solution I will find a ans with g,h,r1and r2.
because r1 and r2 cannot be cut up with the r^2 of w^2=v^2/r^2
for the height of the plane 'h'
mgh=0.5*I*w^2 +0.5*m*v^2
=.5*(.5*mr^2)*(v^2/r^2)+.5*mv^2
solving this give
v=root of (4/3 * gh)[for a cylinder ]
but for a ring there are tro Radios
inner and outer.so how I can solve it for a ring?
I mean that the ring is not thrown in any initial valocity.just as you have put the ring top of the plane and escaped it!
and this is for physics olympiad.not my homework!!
I have got the solution for a sphere or cylinder, in the physics by robert resnic.but cannt solve this problem for a ring.
a ring of inner Radios r1 and outer Radios r2 is falling(free fall) from a plane, which is angled (theta) with the horizontal axis.
what will be itz final valocity?
(plz ans it using the moment of inertia for ring:(.5*m(r1^2+r2^2))
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