Niha afzal

:D :D its amazing the above conversation is making sense :') the curved path thingy

Beautiful simply beautiful sensei the effort is much appreciated I can finally see what's happening here :') which made this thing much more simple:)

Are u referring ti.something like this?

But I think I dnt understand the question properly. .. if the fleas walk in a straight line and its a square cube how do they meet at the center thy must just walk 1 inch... how will they meeet ( this is getting confusing:( )

This was the question ..... Yeah my teacher told me the path willl be curved today I know why thanks to u and special thanks for answering such a stupid question ...

In case 1 the electron moves In a straight line In case two the field lines are shorter at the bottom than at the top Force on electron is towards right the field lines also go from positive to negative I.e towards right .... but the electron is negative hence repels .. (therefore not sure about the path of electron.... it will depend on the fact which is stronger the p.d or the repulsive force by electron) maybe . Foxy john if I were the elctron I would have chose to go.from the bottom ... lesser distance less time

I have a theory question this time ... case 1 if I have two plates and theres a potential difference (p.d) across them 250 v ... an electron is fired from one end to the other end with some speed v m/s Case 2 Now I take the same plates same p.d however the plates are not uniform this time..... willl this have any effect on the speed of the electron? Compared to case 1 ... or will the time change?

Yessssss! !! :D

My working is beneath question

Hmn so the potential energy at thestart of motion convert to kinetic energy (ke ) the ke is max at the bottom when ball is about to hit the groud so the potential energy at the begning converted to k.e Now since the balll after rebound didnt go back to 80 cm some energy must have been lost as heat light .. But in the upwards motion to the k.e getconverted potential energy. Thats all I know about k.e and g.e

I am literally clueless about this question.. the only thing I understand is the rate at which motor works implies power . And its rising at steady speed .so maybe the kinematic eq will come in handy.... how do I get started

Okay okay ojaay maybe we take the height as 80 -8 cm.... bcz we start the height frm center of gravity of baallll and end it at COG which makes a complete diameter

Diameter 8 cm .. 0.08 m

Oh so il take the height as .8-0.04 meters .... Then the p.e will be mass× -9.81 × .8-0.04 ?

I used the kinematic equations To first find mass from the k.e given And in the secound part I used the mass to calculate the new k.e .... I attached my working

Yes .... the squares get cancelled out leaving me with B

Wwavelength of red is longer than blue .. I seee where I was making mistake. ... the freq of u.v is greater than infra.... which crosses D and the ans much be A

B is wrong bcz longitudinal waves cant be polarised because they travel in only one plane ..... C is wrong bcz the relationship isnt correct the amp squared is directly proportional to the intensity not the energy.... B and c are both wrong... But A AND D are both correct :/

Intensity is the brightness of the wave ... and the eq INTENSITY DIRECTLY PROPORTIONAL TO AMPLITUDE^2 relates them And amplitude is the maximum displacement of the wave

Max k.e when the particle reaches the straight lineee.horizontal axis ... Therefore in time T it comes to the straight line twice.... .. if negative max is zero velocity and the straight line is max velocity. ... in time T the particle makes 2 curves .. hence the option is D? Is it

I solved it this way and flunked :/

And this time I have no idea even how to start the problem. I just know one thing I DIRECTLY PROPORTIONAL TO R^2 and the other formulae relating radius is given in the question..... now how to I relate both of them

Two parts are correct ... A ) INDEED the speed of electromagnetic waves in vaccum is same.... 3×10^8.their speed only changes when medium changes. D).THE FREQ of infra red is greater than u.v ... Now how do I go about this problem

My approach for this question is.. The disp time graph will give us the speed .. the speed will give us kinetic energy 0.5mv^2 . Now the disp time starts with a negative displacement. ..the particle at that point will have a gradient (speed) negative . .. but in the k.e eq the sped gets squared .. therefore the first kinetic energy must be positive having some value.... crossing part B AND D which start from zero.... now how do I chose from A AND C.... if my thoughtprocess is correct ...

I did basic calculus .... im still doing my alevels ...therefore I have both physics and maths .. but basic math This kinematics working was amazing.. who knew we could relate kinematics and elctricity like this.... this was amazing seriously yet im scared how will I figure out stuff like this. My best bet is practising a loooot! I find no words to thank you :')