martillo

I don't understand your point. p = mv and dp/dt = mdv/dt + vdm/dt what is different from mdv/dt = ma for variable mass systems like the rocket. The force on the rocket is found to be F =ma what is not dp/dt.

The problem in the rocket's equation is not in its derivation but in the final result. The force on the rocket is finally found to be F = mdv/dt = -vedm/dt and as dv/dt = a the force is F = ma and not dp/dt.

Electrons jump to a lower level of energy and the difference of energy is to the energy of a emitted photon. This is the balance of energy. Now, In my model there is another fundamental particle involved: neutrinos. In my model there are abundance of both in the universe and they can convert in each other. In absorption a photon converts into a neutrino and in an emission a neutrino converts into a photon. There are always available neutrinos near the atoms for the emission process take place.

In my model, any material body in thermal equilibrium with the environment has a stable temperature T. There are photons in in both the body and the environment and they continuously interchange photons establishing a dynamical equilibrium between them. It is assumed that to reach any temperature greater than the 0º K the body absorbed photons from the environment or from from other body before and so on for all the other bodies and environments in the Universe. If you are asking how all that photons appeared in the universe it depends on which theory you have for the origin of the Universe. In my case I don't really know how.

Where are you considering generated photons? in the bodies or in the conductor. I don't get your point. Right, that equivalence is wrong then. Seems you are right. I was wrong in something. Let me summarize. I arrived at : µ(f,T) = [8.π.K3/(h2.c3.(e - 1))].T3 [constant] = 8.π.K3/(h2.c3.(e-1) = 1,01660413x102 in SI units: K-1.kg-1.s (precision of 8 digits) and: Q/V = µ(f,T) = [constant].T3 So the units verify: J.m-3 = [(J.K-1)3/((J.s)2.(m.s-1)3)]K3 = (J.K-1)3.(J.s)-2.(m.s-1)-3 = J.m-3.s Simplifying I reach: J = J.s what is wrong You are right. Please let me some time to review everything now...

The concept of photons as a model for light (and heat and whatever EM radiation) appeared with Einstein. It didn't exist before and the classic Newtonian mechanics was valid with instantaneous fields. Maxwell validated the concept of light as an EM wave with his equations but Einstein introduced the concept light as photons particles travelling at the same velocity c. Then Einstein came with his Relativity Theory imposing the constraint that nothing, absolute nothing can travel at higher velocities even any field which all where treated as instantaneous before. At the same time Hertz experiment on EM waves demonstrated the existence of EM signals travelling at velocity c and validating the EM waves and also the EM fields propagating at c. All the fields were assumed to propagate at c then. In the particles' Physics surged the concept of force carriers and "virtual photons" as mediators for the fields. So they came with Relativity Theory.

It is assumed a contact surface between the bodies and the conductor through which the photons can pass. The units in both sides of the equation perfectly match now. You must consider the equivalence of the units of Joules and Kelvin in the MKS: J -> kg.m2.s-2 K -> kg.m2.s-2 I have found the equivalence for Joule just in a google search and for Kelvin at: https://metricsystem.net/si/base-units/kelvin/ This means MKS unities of Joule and Kelvin are the same: kg.m2.s-2 Yes, unfortunately you are very right in this.

In any hot body there are photons present in the interior of the body. I have already said that this is ignored in Kinetic Theory. It is assumed a body that is transmitting thermal energy ("heat") by conductivity through a unidirectional conductor to another colder body. The hotter body has enough energy stored internally as to be able to provide photons for the heat transmission. I still made a second correction, didn't you see it?

I consider the subject of this thread of high priority in Physics because it profound implications in both the theoretical areas as in the applications in the practical areas. It must be analyzed by real physicists (not an Electric Engineer as I am) and channelized in Physics Science in the appropriated way. The problem is in the formulation of the 2nd Newton's law. It is found that the real equation of force is F= ma and not F = dp/dt even for thee case of variable mass. I have already begun to treat the problem threads here at the SFN forum in 2019 and in 2023: A new evidence surged from the reference of a book published by Dr. Cowan (London University). The participant @studiot posted a photo with the passage of the book involving the subject: I have to abandon the thread because of the lot of days discussing with several ones at the same time without sleeping properly. now I return to the subject with some more expertise and renewed energies. I present the problem in a small manuscript I post here now: The real equation of force is F = ma Today's Physics is stating that the Equation of Force is F = dp/dt. We will analyze the equation of motion of rockets to see that the real Equation of Force is: F = ma A rocket has variable mass in its trajectory and it's important to see its motion equation. Let m be its variable mass at any instant in its movement composed by the mass of the rocket plus the mass of its contained fuel. I have made a search in the internet about rocket motion equations and all the sites agree in the equation: (6) F = m(dv/dt) = –ve(dm/dt) where ve is the speed of the expelled fuel relative to the rocket. They all agree that the force acting on the rocket is due to the expelled mass and is F = –ve(dm/dt) and that the equation of motion is F = m(dv/dt) = ma. I assume the equation has been completely verified experimentally with enough precision from a long time ago. It is evident that in the development it is used covertly the equation: F = ma for the force and not: F = dp/dt By definition p = mv and dp/dt = m(dv/dt) + v(dm/dt). They derive the rocket's equation of motion based on the principle of conservation of momentum but considering the momentum of the rocket with the totality of the fuel (the contained plus the expelled fuel) at any moment and stating dp/dt = 0. After that they derive the equation of motion of the rocket as: m(dv/dt) = –ve(dm/dt) and specifically say that the force on the rocket is: F = m(dv/dt) = –ve(dm/dt) m(dv/dt) = ma then it is clear that what is finally applied to the rocket to determine its movement is the equation F = ma and not F = dp/dt. This indicates that today's Physics is wrong stating the Equation of Force as F = dp/dt. The right Equation of Force is F = ma even when mass varies. Note that the natural derivation of the famous equation E = mc2 by Relativity Theory has no sense since it is based in the wrong relation F = dp/dt. Relativity Theory becomes a wrong theory since it is based on a wrong law. By definition: p = mv With partial derivatives: dp/dt = m(dv/dt) + v(dm/dt) Now as: F = m(dv/dt) Then, the valid Equation of Momentum and Force is dp/dt = F + v(dm/dt) Then, the principle of conservation of the momentum p = mv must determine that dp/dt = 0 when no forces are applied and when there's no variation on the considered mass. It can be observed that this principle can be applied to the rocket as was applied in the cited cases giving the same result. Considering the mass m' of the composed body of the rocket and the total fuel (the contained plus the expelled fuel) which does not vary: F’ = 0 and dm'/dt = 0 Then, the thrust equation can be derived (as below): m(dv/dt) = –ve(dm/dt) where m is the mass of the rocket with its contained fuel. Finally: F = ma = m(dv/dt) = –ve(dm/dt) is the force exerted on the rocket. F = –ve(dm/dt) Rocket thrust force derivation The thrust equation of the rocket is derived here considering the approximation that the mass of the expelled fuel of the rocket is negligible compared with the mass of the mass of the rocket plus the mass of its contained fuel: Momentum and Force equations: p = mv, F = ma = mdv/dt dp/dt = mdv/dt + vdm/dt = F + vdm/dt Considerations: a) masses equations: m = mass of the rocket with its contained fuel me = mass of the expelled fuel m’ = m + me = constant = total mass of the system rocket with total fuel dm’/dt = dm/dt + dme/dt = 0 Then: dme/dt = -dm/dt b) velocities equations (one dimension): v = absolute velocity of the rocket ve = velocity of the expelled fuel in relation to the rocket assumed constant u = absolute velocity of the expelled fuel ve = v – u = constant dve/dt = dv/dt – du//dt = 0 Then: du/dt = dv/dt Derivation: Total momentum of the system rocket with total fuel: p’ = mv + meu dp’/dt = d(mv + meu)/dt = mdv/dt + v/dm/dt + medu/dt + u/dme/dt Considering: du/dt = dv/dt and dme/dt = -dm/dt dp’/dt = (m + me)dv/dt + (v-u)dm/dt As v – u = ve and considering me << m (m + me ≈ m) then: dp’/dt ≈ mdv/dt + vedm/dt and as dp’/dt = 0 then: mdv/dt ≈ -vedm/dt Finally F = ma = mdv/dt ≈ -vedm/dt under the approximation me << m Then, the rocket thrust force is: F ≈ -vedm/dt

I have read the article at arxiv (https://arxiv.org/pdf/gr-qc/0008009.pdf) and it talks about the invariance of the constants with time but I don't see anything about that as a consequence of this the fields (particularly the E and B fields) must propagate at the finite velocity c. This is a different thing. As I already said to you some time ago the unique experiment that seems to prove the finite velocity of propagation of the fields is Hertz experiment on the EM waves. The experiment seems to prove a finite velocity propagation of the Em waves and the EM fields. I have a new interpretation of the experiment showing how antennas could actually emit photons and not waves and all our communication systems could be actually based on absorption, emission and transmission of photons and not waves. This way the experiment could demonstrate the existence of "electromagnetic particles" the photons and not "electromagnetic waves". It could be the case of instantaneous E and B fields and an EM particle (the photon) travelling at velocity c. I find interesting that Einstein also disagreed with the EM waves concept of light. At Planck's law page at Wikipedia can be found: "Thus Einstein was contradicting the undulatory theory of light held by Planck. In 1910, criticizing a manuscript sent to him by Planck, knowing that Planck was a steady supporter of Einstein's theory of special relativity, Einstein wrote to Planck: "To me it seems absurd to have energy continuously distributed in space without assuming an aether."[135]"

Well, then I must review that. Please, can you give me some link o reference about the subject? This subject is something of major importance to me.

But isn't that a consequence of Relativity Theory? If I disprove Relativity that constraint would not apply anymore.

But it would be because information is actually carried by photons and photons are particles that do have their velocity limited on c. Not because of the fields that could be instantaneous.

Instantaneous action at a distance forces was something considered in all the development of Physics Science before the apparition of Relativity Theory. It is a central point in Newtonian dynamics. Now I see everything on my models and all my work stucked by Relativity Theory. I think I could make a try in disproving Relativity Theory here in the Speculations Forum. It is based on a review on the formulation of Newton 2nd Law. I have already tried this here in a thread in this forum ( ) and I think I quite reached the goal but I had to abandon the thread because of the lot of days discussing with several ones at the same time the entire day without sleeping properly. I couldn't continue going on that way. I think I could return now with the same approach presenting my same argumentation and experimental evidence and an excellent new evidence that surged in the discussion and with more expertise and renewed energies. May be I start a new thread soon.

Thanks very much for the comment. +1. I will try arxiv, something I have never done. May be I could have some luck... I mean instantaneous action at a distance of forces. May be this is actually experimentally inobservable at subatomic scales, I'm not sure. The model unavoidably ends assigning mass to photons for them to have separated internal energy and kinetic energy. I have thought, in the same kind of reasoning for considering virtual particles, to assign an hypothetical mass but this will be easily disproved by some relativistic experiments I think. I think those experiments can actually be interpreted in a different way providing a new way to explain them but is something not so easy. Too much things to be explained at the same time. A huge task...