Sarahisme

thanks for that Aeternus, that helped a lot! Sarah

isnt the first derivative only one sided too? (at x = 0) ?? and therefore the first derivative does not exist at x = 0 ??

ok, can i ask you about a particular example about the null space of a matrix? cause there is something strange with it i think...?

oh ok then, thanks matt

oh can i ask one other quick question/example.... about finding the null space of a matrix?

sorry bout that matt

sorry, i've never heard of vector space..?? and i gather i got part i) right then ?

hey, just double checking this stuff (i have only just begun this topic in maths and so i am a little shaky on it) is the answer to this: i) no , because the zero vector is not in the set H. ii) yes, but i don't know how to explain why, i guess if you let s and t be zero, then the zero vector is part of the set L , and obviously if you add any two vectors it will still be in L and if you multiple by a scalar it will be too... anyways, yeah as i said, i'm a greenhorn with this stuff, so take pity Sarah

3u^2=-2(u-8) doesn't solving this just give you the (x,y) corodinates on the oringial curve, and so you would not actually be finding the distance by just doing that?

hmm ok, i did part a) a different way, but i suppose it was the wrong way then oh well, thanks for you help matty (do you mind being called matty?)

yeah but its always good to make sure its correct i suppose

did you think my part a) answer was right?

lol....so i take that as i got it correct then?

hey peoples , if anyone is willing could the please give me few hints for this question.... i think i have done part a) i get for part a) ~5.271 units but i have no idea how to "use" the extra information given in part b) ... anyways aghh been tring for hours and hours, lol , you know the feeling Sarah

hey just wanted to know if my answer is good?...thanks guys my answer would be X = A°(C - D) - B° where "A°" stands for inverse of matrix A ...etc...

ok, so so part c should be c) f''(x) is either -2 or 2, so not zero and d) no not necessarily

Hey can i ask if my answers to this question are correct...? a) yes, because f'(x) = 0 at x = 0 b) yes, because there exists a tangent line at x = 0 (because of part a) and the concavity is of a different sign on both sides of x = 0 (i.e. f''(x) is -ve one left and +ve on right) c) no it is not true, because f''(x) = 2 for all real x in the domain d) no, as can been seen in this question Sarah

thanks everyone

lol i need to know if am doing this right....vitally! (ok thats not the right word, maybe quickly? i dunno anyways, i'm rambling...) the question is: "identify the functional groups present in indigo" i would say there are the CO and NH functional groups (whatever the names of them are?) how far off am i? lol or right on the money? (hopefully! ) this is the structure:

don't worry bout it guys, i got it now thanks for replying anyway though Sarah

Hey peoples... i have a quick question... if i want to find the moment of inertia from a the gradient of a graph... and i have taken a whole lot of measuremants that vary time and mass... what would i do with these three equations: (i have been fiddling around with them for hours and getting nowhere, i was looking for a directly proportional realtionship but yeah....probably not the way to go i guess ) T is tension and so i suppose varies with mass h and S and r are all constant , oh and g is constant too of course equations: any help, i'd love it! Sarah

would anyone be able to help me with some questions about two very short java classes? i have come up with some answers of my own, but yeah, i'm not sure how correct my answers are.... the 4 questions are: 1. The data attributes m, n and grid in the HeatGrid class are declared private, and methods such as gridHeight(), gridWidth() and copyGrid() are provided to extract their value. Why is the better class design than simply declaring those attributes as public? My answer: So other classes accessing them cannot modify those data atributes, i am not sure why this is better class design. 2. Why must the (global) constants in HeatSim.java be declared static ? My Answer: because HeatSim is what you run first and so you don't create a HeatSim object, you just access its methods, thus the need to make them static. 3. Assuming HeatGrid has been fully implemented, during the execution of the statement HeatGrid = new HeatGrid(inGridFile), how many objects of HeatGrid, double [][] and Scanner are created? My Answer: 1 HeatGrid object, 1 doulbe[][] object and 1 scanner object Which of these objects must still exist after the statement completes execution? 4. For each of the classes HeatSim and HeatGrid, identify the client and supplier classes (including library classes). My Answer: So far this is what i have done. for the HeatSim class, i said that the supplier classea are: double int boolean String Math Class viewgrid class array and the clients for the HeatSim class are: HeatGrid class if anyone can help me i will but up the VERY short code to these two classes. I am really stuck and any help woould be greatly appriciated! Lots o love Sarah

yes thats what i am saying ...to solve it, there are only certain cases which work.... so yeah can you think of any other cases? or are any of my cases wrong?

well couldn't hurt could it

no they are not