Sciencegeeknm

Hi, Sorry it is heptanone I have drawn. The target molecule is one I have just randomly drawn. I do not intend to make it. I study organic chemistry as a hobby/interest and watch online lectures. The lectures are now covering synthesis so I have tried to do one myself. I learnt that the starting material should only be 4 or 5 carbons and possibly an alcohol? Im trying to do a retro synthesis here but probably not very well. How would you go about making this target molecule? Or have I drawn something which can't be made? Thanks Nick.

Hello, I am a complete beginner to synthesis and wondered if someone knowledgeable would mind checking these steps to make 5-Bromo 3-hexanone When you make the two molecules how is the carbon carbon bond formed to join them together and make the target molecule? Thanks.

Thank you for your answer it really helped. I'm glad I found this forum.

Hello, This is the first reaction in the synthesis of C60. As you can see from the attached picture the starting molecule is benzene with a chlorine attached and a bromine para to it. After a grignard reaction with Mg and MeCHO(Acetaldehyde) you get a chlorine attached and a methyl and alcohol para to it. Can someone please confirm that my thinking below is correct on how I think the initial carbonyl is reduced to an alcohol. 1. The bromine which was kicked of by the Grignard reagent now carries a negative charge and attacks the carbon double bonded to the oxygen. The 2 elections from one of the double bonds goes onto the oxygen 2. The oxygen now attacks the adjacent hydrogen and is protonated. The bond which was attached to it collapses and kicks of the bromine? I might be completely wrong! Many thanks. Nick.