apixy

I came up with the equation, for the test in 2 days, and to verify it I searched it up and found this. I came up using this... $E = pc$ We know 2 equations that are true, and they are: $E=\frac{hc}{\lambda}$ $... \lambda=\frac{h}{p}$ Substitute and you get your equation really... $E=\frac{hc}{\frac{h}{p}}$ Which is equivalent to $E=\frac{hpc}{h}$ The 2 'h' cancel out to leave you with $E=pc$