Hi, trying to determine the forces acting upon this mechanical system, Pics attached. The mechanical device works in a similar fashion to a crankshaft and piston. the crankshaft contains 2 gears, 1 on the crank journal which is fixed to a lever that runs along a track on a roller, the second gear is the sun gear that's in the center of the crank, this gear is not fixed to the crank, and runs through the crankshafts central axle, "a double axle". Fig 1 split crank image. shows a simple view of the system.
Fig 3-4, 3D image of system. both crankshaft systems are the same, they are placed 180 degrees apart opposite each other e.g. a flat 2 cylinder engine. the gears have the same amount of teeth. the shafts of the central gears, that exit each end of the crank turn at twice the speed of the crank due to the planetary type gear system. these gears connect via chains and sprockets to pulleys. The pulleys have different diameters, in this example the diameter of the green pulley is 1/10th the diameter of the Pink pulley. Between these pulleys is a tension spring which is connected to cables wound around around the pulleys. the green left pulley receives a counter clockwise force, the pink right pulley receives a clockwise force due to the tension of the spring and cables. .
Fig2, front view of the cable and spring not added in the 3D images, difficult to do). the left and right cables cant unwind when under tension due to the levers on the tracks preventing them to turn, the left side lever has a CW force, the right side lever a CCW force. Both geared levers are trying to lift up. if the cable was cut and the pulleys were turned CW 720 degrees , the crankshaft would turn 1 revolution CW due to the 2 outer geared levers trying to turn CCW which transfers a rotational CW torque on the crankshaft. What actually occurs in this system !, is it in equilibrium, or is there more torque on one side ? If it does what i believe it does, it can't be! Thanks Kurt.E
