Sriman Dutta

There are millions of books available in the market on mathematics. You need to choose the level.

Oriental philosophy of the East is still in one way or the other exists. Max Mueller was the first European who dig up the classical teachings of the Aryans in the Vedic Age.

How ?

A photon is a massless particle and I have never heard about a photon's volume.

Hi DimaMazin I see that the formula you posted is quite identical to the Doppler's Effect equation.

Energy is an intrinsic property of all bodies regardless of their mass. In other words, the energy that is within a body can be accessed or cannot be, in the form of work. Suppose there is a system which contains potential energy because it is near to a gravitational source. This energy can be utilised to perform useful work, by changing its state of motion, i.e., by moving the body we can convert its potential energy into kinetic energy. Mathematically energy can be defined as the force ( may be abstract ) times the displacement.

Well done Dr. Krettin and Function. Wonderful calculations Raider.

Thanks now I have learnt the velocity addition formula in SR. Thanks for all your help.

DimaMazin from where do you get v1 and v2 ? Can you explain the context?

Antonio in The Merchant of Venice had some kind of unexplained sadness in the beginning of the play.

You can buy an infrared camera that works excellent at night as it shows picture based on thermal radiation given out by bodies. You must have seen such things in the TV programs in channels like NGC and Animal Planet.

Suppose a glass tumbler contains a certain number of bacteria. A scientist found that the number of bacteria doubles itself after every one second by asexual reproduction (completely hypothetical). He observed that after one minute the glass was full of bacteria. Can anyone tell when was the glass half-full ?

What ? You want to see beyond photons ? I think nobody and nothing can SEE beyond PHOTONS, if you know what I am speaking. But, you can see beyond the visible light spectrum by using infrared cameras.

Swansont can you please explain it deeply (showing the equation and how it fits right) ? Sorry for troubling you.

This new solar panels can be called hydro-solar panels.

No, I think !!

Thanks for that. Now I give here a case to consider. Suppose there is an observer who is travelling at a very high velocity v, v = 80% of c. He finds another light ray travelling parallel to him. According to special relativity he must find the ray travelling at c, as opposed to the classical view that he would see the ray travelling at the velocity of c-v. Now can anybody prove that he will find the light ray travelling at c and not at c-v ?

So now I get it. Thanks to all of you. Now I understand SR. But still I haven't got a mathematical model for explaining the time dilation due to speeds near to c and the phenomenon of gravitational time dilation. Can anybody provide me that. ?

Oh I see. thanks.

testing [math] s^{/frac{1}{2}} = 0 [/math]

So does the energy of the photon decreases actually ?

OK fine but that doesn't work for my question.

To colonize Mars we have to adjust with a typically CO2 concentrated atmosphere.

According to Einstein's Special Theory of Relativity, time passes slowly for an observer when the observer is near a gravitational source. So, if there are two observers, time passes slowly for the one whose distance from the gravitational source is less as compared to the other. So, time dilates for the lower observer in relation to the upload observer ( considering the case in a gravitational potential well). However, if the two observers are not allowed to communicate or see each other, they would never realize the time difference. The direct result of the gravitational time dilation is gravitational redshift. For an upper observer, time passes more quickly than the lower one. If a ray of light travels out of the potential well, the ray would be redshifted for the upper observe ( because frequency of light is inversely proportional to time elapsed). This means that the energy of the released photon decreases because E=hf. However my intuition tells me that the energy only seems to decrease to the external observer as he is placed outside the photon's frame of reference. Am I correct. ?

Here's the relationship between joule and electron volt. 1 eV = charge of 1 electron X 1 V = 1.6 X 10^-19 C X 1 V = 1.6 X 10^-19 J