Westerwolde

Hello, Sorry for my late response, I was busy my other homework, this assignment I have to hand in a few weeks. This is a task that I have to make for mathematics (homework) I use google translate, I'm from Holland. I understand what you write above. First let me mention some: The first question was: lead a formula for the dimension b (x) at a distance x from the left bearing. Given: The beam has a varying cross-section. It is given that the dimensions at the end of the beam is determined by the relationship: b (l) = αb (0), with α less than or equal to 1. To help us showed our teacher this task 1, but he said clearly at; this should yourself be able to prove. The following formula is derived by our teacher; b(x) = b(l) + ((l-x)/l)* (b(0)-b(l)) I think the formula is valid for a distance from the right bearing. Therefore he said clearly defined ; this should yourself be able to prove. I would say that the function of the left bearing: b(x) = (b(l)-b(0)/l)*x + b(0) What do you think of this ? Okay now returning to the moment of resistance W (x) The function of the moment of resistance must also apply to the cross-section b (x) at a distance x from the left bearing. Can we then the formula for the resistance moment substitute in the function b (x)?

There has been given that the dimensions are determined at the end of the beam by the relationship : b(l) = α b(0) with α of less than or equal to 1

Can someone help me?

Hi, I need to derive a formula for the moment of resistance W (x), at a distance x from the left bearing. This W (x) satisfies the formula: W(x)= b(x)^3 / 6 Given: applies for a rectangular cross-section: W= b*h^2 The function b (x) : b(x) = b(l) + ((l-x)/l)* (b(0)-b(l)) How do I do this?