elmitodeherta

I don't think so, because there is both different emissivity and reflection, should be different temperature

First calcualte the energy emitted by a perfect emitter ( a black body) then multiply it by experimentally determined emissivity (engineering tables are available) to obtain the emission from your wall. As to reflectivity, this coefficient is also available from engineering tables, and will tell you how mauch irradiated energy is reflected. So for instance a polished metal has low emissivity bu high reflectivity. Does this help?

Hello,I would like to calculate the difference between a white surface wall surface and the same kind of wall but with brown outer surface. I would like to know the reflection and absorption indices and then calculate the surface temperature of the wall in the two solutions at the same temperature as the outside air temperature. How could I proceed?Thank you in advance.