Vmedvil

1/Lp is, look how many cycles happen.

1/Lp = n, is what i am saying for a meter of space.

The value of n in that system for a meter.

Yes, then it does not need converted. You would find there are many more cycles of C , tpC in a meter than Lp , there are 1/Lp of those cycles.

How many changes in a planck length size in a size that is a meter.

that takes it into all possible states in a meter, if it is already on Planck scale it doesn't need to be scaled up.

Oh, see I must have missed you saying that, then yes just Lp would work and not 1/Lp wish you had said that long ago.

GR is incompatible with QM in the present state. SR can be merged with QFT not GR, along with GR with SR which makes SR a good bridge for all of it once put in Laplace form being the same Laplace used in QM, this is all about how screwed up QM is while still being correct. The real test will be not all the other variable but these two (φ,S) , Those others are being checked just for shits and giggles, I kinda knew that GR would work in SR. (ωs) that why I took EFE to irreducible they should not ever change, the others can but that one cannot to join QM at Laplace, which is why you were right when I should not even touch the EFE's state besides solving it for Gaussian curvature which is ((1/2) R = K), but making it irreducible I did the equivalent of observer effect it. So, as I screw with QM when it doesn't work in that state I can change it without worrying about GR., I did the same to QM. as ∇ = (d2/dx2 + d2/dy2 + d2/dz2)1/2 Irreducible.

Oh, I agree it is happening on the Planck Scale, which is why I wanted to see what that "Toy Model" said on the Planck Scale.

Exactly, but the energy is released as light particles called photons being neutral as charges cancel.

Even in Parts in Big O notation this is Rank 6 as nested to a high degree, I dunno what rank the entire EQ is.

well, you know what at-least this way I don't have to proof it and wolfram will do it, what did you think Fusing it all into a single field would be pretty, wolfram said that my equation worked without all this and the Einstein part worked.((x,y,z,t,ωs) Function as intended.

Okay, expanded to a wave which we will now always call Graviton wave "Mother nature's Massive boobs" *zooms in* I feel like a peeping tom somehow, well now we know how those are made Inverse sine or Inverse cosine cellular reproduction curve ladies and mother nature has many more than human females. In any case, if that is too sexualized then we can just say "Mother Nature's Massive Hershey kisses" or Graviton wave. Hold on I gotta post something somewhere where kids wouldn't see this.

Defined 1 as Reduced Planck's constant and. Defines as 2ħ Now Defined that as this. Split 2ħωs = ℏωs + ℏωs Eb(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,u) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + ((∑j∑iaji)) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + ((∑j∑iaji)) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + ((∑j∑iaji)) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(1/((1-(((2MbG / Rs) - ((∑iMiR2i)ωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+G(∑iMiR2i)/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + ((Ar(X) + (Ebx ε0 μ0 /mu) - Ar(XZ+)/Z) / mu)2)(1/2)(1/e((E - μ)/T)±1)(ħωs + ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2))(Mb/ε0 μ0) Lol, I just looked at this picture in a very different way, did you know that mother nature has almost perfect breasts? I had to say that, cause it looks like it with that curve.

Furthermore and do you see this term repeated, which says it is the same as C2 (2ħG/ε0 μ0) and I noticed that typo in the last picture. Intertia should be Inertia. There we go.

There is nothing sub planck there and all those natural units have SI values like I said this is no for you to use but a computer, ultra simple version since it never changed Photonlike Es = ℏωs Particlelike annihilation. Ea = 2ħωs = ℏωs + ℏωs Inverse Moment of Inertia Curvature and Inverse Mass Curvature ωs , which has a Irreducible EFE in it. ωs = -1/(Is(Guv - Ruv/-guv)1/2 + Mb(Guv - Ruv/-guv)1/2) Those are the All the ωs Terms in the equation, but it is inverse so it is gonna look weird.

j = Number of Probability currents, All of it is Metric system for units.

Thanks Superpolymath for your assistance. me = (Ar(e) / mu) , Ar(e) = (Ar(X) + (Ebx /muC2) - Ar(XZ+)/Z) , In any case, that adds the residual SNF. Eb(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,u) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji.) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(1/((1-(((2MbG / Rs) - (Isωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + ((Ar(X) + (Ebx ε0 μ0 /mu) - Ar(XZ+)/Z) / mu)2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2))(Mb/ε0 μ0) Where aji is the last one left undefined. Which will get summed along with ∑iIs =(∑iMiR2i) across space as that didn't effect it. Eb(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,u) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji.) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(1/((1-(((2MbG / Rs) - ((∑iMiR2i)ωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+G(∑iMiR2i)/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + ((Ar(X) + (Ebx ε0 μ0 /mu) - Ar(XZ+)/Z) / mu)2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2))(Mb/ε0 μ0) Where aji = (∑j∑iaji) Eb(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,u) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + ((∑j∑iaji)) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + ((∑j∑iaji)) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + ((∑j∑iaji)) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(1/((1-(((2MbG / Rs) - ((∑iMiR2i)ωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+G(∑iMiR2i)/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + ((Ar(X) + (Ebx ε0 μ0 /mu) - Ar(XZ+)/Z) / mu)2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2))(Mb/ε0 μ0) i = Number of objects and j = I dunno.

Okay, I know how to define it, I will just use an electron then take it to a constant for Molar Mass constant mu and Nucleon Binding Energy, which is a weird way to go the SNF for this. Eb(x,y,z,t,ωs,ωp,M,I,k,φ,ρ,me,S) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji.) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(1/((1-(((2MbG / Rs) - (Isωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + me2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2))(Mb/ε0 μ0)

For Instance, Lagrangian form. L'(x,y,z,t,ωs,ωp,M,I,k,φ,ρ,mρ,S) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji.) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(((1-(((2MbG / Rs) - (Isωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + mρ2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2)) As in SR Where L can be wrote as Δx then becomes which in that form is like saying (Δx2 + Δy2 + Δz2) ∇'(x,y,z,t,ωs,ωp,M,I,k,φ,ρ,mρ,S) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji.) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(((1-(((2MbG / Rs) - (Isωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + mρ2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2)) which L is still there but I brought Schrodinger's EQ through it in solving ∇ form. (note: to swan) back to Energy solving form. Eb(x,y,z,t,ωs,ωp,M,I,k,φ,ρ,mρ,S) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji.) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(1/((1-(((2MbG / Rs) - (Isωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + mρ2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2))(Mb/ε0 μ0)

I know it is a Lagrangian its a string. Lagrangian is a function of the generalized coordinates, their time derivatives, and time, and contains the information about the dynamics of the system

Ya, basically but in strings it is defined like this which the Dirac Propagator is like saying Movement in direction in QM and QFT, with a probability of happening.

Grabbed the wrong post post or I mistook your meaning of "intelligible"

Vibrates another direction that is not (x,y,z), you know how gravity pushes into hyperspace this pushes into "Subspace" the other forces.

You know what we are just going to assume Einstein got it right and not worry about that since it is pretty accurate to reality not having many things it cannot do besides the corrections for QM which was totally not right it does happen it is odd. Things Einstein Got Wrong. Missed a mk on retransform. Eb(x,y,z,t,ωs,ωp,M,I,k,φ,ρ,mρ,S) = ((ħωs)((|(Log(DgDaDψDφ-W)(((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji.) - V(φ)/-Dμ2)|)-e2S(r,t)/h)) - (Mbωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2)Rs2/2)((|(Log(DgDaDψDφ-W)((((2ħG/ε0 μ0))Rs -(1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h))) / (ħ2/2Mb)((|(Log(DgDaDψDφ-W)(( ((2ħG/ε0 μ0))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμDμψi +(ψ-bar)iLVijφψjr + (aji) - V(φ)/-Dμ2)|)-e2S(r,t)/h)))1/2(1/((1-(((2MbG / Rs) - (Isωs(Guv - Ruv/-guv)1/2 + (S2/ (3GMb/2(1/ε0 μ0)2Rs3(Rp x vp)+GIs/(1/ε0 μ0)Rs(3Rp/Rs2(ωpRp) - ωp))2))/2Mb)+ (((8πG/3)((g/(2π)3)∫(p2 + mρ2)(1/2)(1/e((E - μ)/T)±1)(2ħωs)) - ((ksRs2/ε0 μ0)) + (Guv - Ruv/-guv))1/2(ΔKiloparsec)))2/(1/ε0 μ0)))1/2))(Mb/ε0 μ0) Mordred on that equation I got from you what was m2 in it defined as, which I gave a mp2 label, I will expand aji based on what it is.