Vmedvil

Dark Energy on the Universe acts like Angular Momentum on a BH, The Angular Momentum expands the Rs From increased mass where Dark Energy Expansion Ru From mass. So Dark Energy is probably like a photon just as a photon can escape a BH's Gravity well, the Dark Energy Particle can escape the Universe's Gravity well, which makes me wonder if the Energy-Mass of the Big Bang was caused by a huge Boson hitting our universe with similar properties to the photon, Gravitational waves, or Dark Energy from another universe. Which is where this leads you to Wormholes which is where this actually agrees with Super Polymath as whatever caused the Energy-Mass of the Big Bang was not from our universe and Energy cannot be created nor destroyed. Where smaller Wormholes will lead back into our universe being directed by Weak Quantum entanglement like a magnet to the Spin opposite state. The Larger of these two would require Strong entanglement to connect with the other universe or it could be vice versa, that is unknown, but I would imagine since Strong QE is faster than Weak QE that it would be this way due to the fact that distance in space would be nothing compared to distance in universes thus a greater velocity is required to reach them then itself in a different part of space, but also you could use the logic that it is the other way around because the distance is shorter between the universe and itself in another part of space so the connection would be faster versus a slower connection between two universes being more distant.

What I think now is Dark Energy is the Cherenkov radiation of that angular momentum during a decouple of the Strong-Electroweak into Strong Nuclear Force and Electroweak like the Higgs Mechanism Cherenkov radiation is mass during a Electroweak decouple into Electromagnetism and Weak Nuclear Force in Tachyon Condensation.

Which goes back to why I said "Punch a wall" we need more curvature to balance out Dark Energy in one of my first posts.(Punch a wall) cause you cannot change this little problem without generating curves explained here (Expanding Universe), Where BH and SMBH are actually damaging this universe which will someday collapse as more form stretching it to death. Thanks to a Matter high Density and Spin with more energy-mass consumed. which explained why this universe began in a boom, that BH must have been highly unstable with that much dense mass (Gravity Magnitude) and Rotation against it, which must have vibrated with expansion and contractions that were violent when it exploded like a supernova. So, what caused the big bang Rotation overcoming gravity @ C, why did this happen Not the slightest clue besides it was "Too Massive". Whatever made it through into this universe was definitely not suppose to be here, why do you say that you may ask? "Because what it did was impossible for this universe to do at that scale." as they are supposed to emit hawking radiation and grow small enough to evaporate, which it being "Too Massive" may have caused a Big Rip within itself. Where we may want to put a "Do not Feed" sign on black-holes as causes our universe to fall apart, which is why here(Dark Energy/Matter Related) I said that Dark Energy may be something not created ever again as the Strong-Electroweak were coupled then the Inflationary period then decoupled into Electroweak and Strong.

More on Double floats(Double floats) and the meaning of the ... (Meaning of ...) So, basically what is needed is a Quadruple Float and ... does actually mean infinity which in double float is expected as it should resolve it like 4.4704601196572883072076801920048 * 10^208 being Volume =(4/3)(1/(tpC)^2)^3 in meters, as the number of Planck time(Time Frequency per second) C(Velocity of Light and Time with infinite energy) equal a meter, which may actually be infinite as it is for energy that calculation due to it hits near a asymptote which is why a Radius defined fixes it like Rs which is a static BH @ C's Radius depending on mass which is energy which turns into another infinite loop, but E = MC2 was made. Where this gives the energy-mass required to make an infinite gravity well(Potential Energy) is Rs , where mass then begins to increase the Rs as Mb or Eb gets larger which then lowers the gravity well with angular momentum, otherwise it would get smaller Rs as mass increased. Which is why BH look like this. Where SMBH look like this. Look at the magnitude of that angular momentum otherwise it the states would be reversed if that ratio were reversed in Schwarzchild Radius or Rs So, what is Dark energy the spin caused from all the mass in the universe, which goes back to the Friedman equation, why are Matter-Energy density and Dark energy both plus.

Well, whatever I will let CS advance until then double float says infinity so accurate for an electron radius which is about half as close as needed being 10^-16 vs 10^-35 until Quad floats are used because it should be a number and not infinity which that number should be around, Volume =(4/3)(1/(tpC)^2)^3 , which is 4.4704601196572883072076801920048 * 10^208

Is there a triple float?

Explain this in detail I am a little hazy on the finer details of a double float. How and why does it define these as the infinities.

I think the ... is where the computer stacks at on a double Float calculation, but it ended operation when it noticed it got near stack overflow. Double Float Meaning Stack Overflow meaning So by infinite it meanings smaller than The 53-bit significant precision gives from 15 to 17 significant decimal digits precision (2−53 ≈ 1.11 × 10−16). If a decimal string with at most 15 significant digits is converted to IEEE 754 double-precision representation, and then converted back to a decimal string with the same number of digits, the final result should match the original string. If an IEEE 754 double-precision number is converted to a decimal string with at least 17 significant digits, and then converted back to double-precision representation, the final result must match the original number. Then again it does define infinity and negative infinity in a double float. So we can at least say that it calculates it better than a computer on a double precision float which would be slightly below femtometers in scale which is within the size of an electron at 10^-16. Therefore, a proton has about 1836 times the mass of an electron. The best estimate of physicists is that the radius of a proton is about 8×10-16m and the radius of an electron is about 10-16m . If they are correct, then a proton has about ten times the diameter of an electron enough to call the 52 zeroes and 11 ones as repeating like π.

Okay Now, I have a idea of how to make this 20 Teraflops by bridging the two computers together which is what that data chart is for which the max exchange between the two is 1.1 GB/s Which acts like a i9 12 core 24 thread 2.9 GHz with a Tesla 40K or Tesla 80K somewhere in-between those two.

Where to stop the infinite looping around and around the equation you need to add a Radius which we will add the Schwarzchild Radius solved for C^2 of Rs

I noticed a typo/mistakes here "Well, the Quantum numbers of an electron are equal to this expression in X = R Cos(Θ) , Y = R Cos(Θ), Where Z = (I(d/dx) J(d/dy))^(1/2) Where Z = 0" It should be X = Rjk Cos (φ) , Y = Rjk Sin(φ) , Rjk = (I(d/dx) + J(d/dy)^(1/2) , Where Z = 0 , I said that Z = R, that was wrong it does actually equal zero with no dimensions, Where ω^2 = (ΔΘ/Δt)^2 with a relative Magnitude of I for each Energy-Mass which can be in energy or momentum. Spherical coordinates (r, θ, φ) as commonly used in physics (ISO convention): radial distance r, polar angle θ (theta), and azimuthal angle φ (phi). The symbol ρ (rho) is often used instead of R. Where Rjk is like the Reimann curvature Tensor. as (u,v) mean that same as (I (d/dx))(J (d/dy)) -Which is like saying (x,y,z,t,θ,φ, I) or (x,y,z,t,ω,M,I) , where (x,y,0,t,ω,M,I,) which mean does does equal zero if (R = Y + X - 0) Where φ = Tan-1(x,y) Where X = R(Cos(θ) and Y = R Cos(θ)

The Idea of wormholes in large stellar space comes from Einstein and Rosen , which is described like this, which comes from the Schwarzchild Metric, the Kerr Metric does not say that it happens the same way.

Here is the build list that generates that good hunting happy black friday. 2017-2018 Newegg Area 51

Well, the Quantum numbers of an electron are equal to this expression in X = R Cos(Θ) , Y = R Cos(Θ), Where Z = (I(d/dx) J(d/dy))^(1/2) Where Z = 0 Where the Metric under the ()^(3/2) is spin versus a gravitational pull of equal magnitude across Schwarzchild Metric for static moving objects to Kerr Metric for a body of mass, Which I = The summation of all they (tpC) movement versus time is displacement vectors in a Brother of the SO Group which is SO(8 x 4) The Set would be For if it exists as a string of quantum entanglement across two opposite but equal spin states. which this set says that when the spin states are equal within the system that this is a linkage generated. Then a D - Brane forms between the opposite spin states in the mass which has been done in photons where Q entanglement is the operator of Wormholes in the Einstein-P Bridge where the D brane equal for the Universe space-like solution can be found in Superstring as P = Brane Size of (2) and as disconnected across space Strings being Closed Strings q = 1 where q = may also equal (2) as a D-brane sheet between two spaces in a Wormhole Open String lattice.

Well, Someone has to work the backbones of bitcoin otherwise it would just error out and say "Unable to complete transaction"

Yeah, I am going to be using mine for protein folding and Bitcoin mining strictly for the next couple of years. Days to generate one block mining solo: 3082.99 Day(s) (can vary greatly depending on your luck)Days to generate one BTC: 246.64 Day(s) (can vary greatly depending on the current exchange rates)Days to break even: 68.71 Day(s) (can vary greatly depending on the current exchange rates) Bitcoin Mining Profitability Calculator Time Frame BTC Coins USD Power Cost (in USD) Pool Fees (in USD) Profit (in USD) Hourly 0.00016894 $1.33 $0.08 $0.00 $1.25 Daily 0.00405450 $31.82 $1.80 $0.00 $30.02 Weekly 0.02838153 $222.77 $12.60 $0.00 $210.17 Monthly 0.12163515 $954.71 $54.00 $0.00 $900.71 Annually 1.47989431 $11,615.68 $657.00 $0.00 $10,958.68

Lol, they are just + or - signs ways in the direction of the field, just as charality exists in chemical structure so does it in matter structure, they a supersymmetric across this. In this case, it is across charge so the magnetic field lines both in the opposite direction, but class how your left hand is different than your right.

So I just calculated this configuration to be equal to a Area 51 medium build. http://www.dell.com/en-us/shop/dell-desktop-computers/alienware-area-51-gaming-desktop/spd/alienware-area51-r4 If you want it build by dell and not yourself. If you build it yourself do not forget Thermal Paste for the Precessor Artic silver thermal paste is probably best for connection between it and the watercooler mount like a normal processor. https://www.ledsupply.com/accessories/arctic-silver-high-density-silver-thermal-compound?gclid=Cj0KCQiA0b_QBRCeARIsAFntQ9pc17QytZtPL0h3LqaKHesN8Mb5HhlSKgbMxCnuGKqoxNlUl75UnhEaAm4PEALw_wcB

You know your right that Card is actually supposed to be paired with a 6 core processor as 6 * 64 = 384 bit where 4 * 64 = 256 bit, where that card's bit is 352 bit which is closer to 6 cores than 4, I know how to OC to sync it now, 1.375 a quad-core, so 5.775 GHz or lets just say 5.8 GHz, but that is the memory interface so it is something like that, which each core is clocked to 1.569 GHz and there are 3584 cores where 5623.296 GHz or 5.623296 THz is all of them. Well, I dunno at this point I get way different numbers but (1.5)4.2 GHz HyperQuad = 1 HyperHex at 4.2 GHz or HyperHex at 4.2 GHz = 6.3 GHz HyperQuad. 3.7 GHz HyperHex = 5.55 GHz HyperQuad. So, somewhere between 5.6 GHz and 5.8 GHz which we will say 5.7 GHz will be perfect for that card around that, if it was meant to sync with a Hyperhex @ 3.7 GHz, let's assume that it sync with the processor at the same speed at its memory as a estimate, so 1.35 a Hyperquad of 4.2 GHz is around 352 bits within ±1.818% , correct me if you know a better way to do that.

Where I would have to use something like that in the board only supporting 8th gen. Ya, no what processor fits that board "Only 8th gen with a 1151" that X and XE are 2066 where that 7700K is 7th gen, oh the coffee series 8th i7 Ya, I would consider if there were any left. Honestly, that looks unstable with a 1.0 Ghz Turbo or 1.4 Ghz Turbo Ya, that looks like a experiment they were doing with turbo almost by they I mean "Intel", the question is would the turbo stay stable clocked at 6.9 GHz with a turbo of 7.9 GHz or even 5.9 GHz with a turbo of 6.9 GHz where it is a 6 core though with 12 threads, I dunno. Well, the .5 GHz turbo is stable way overclocked, but would the 1.0 GHz or 1.4 GHz turbo stay that way.

Well, No I know that, that processor is not as powerful as that card but I dunno by how much, which is why it needs to be OC'd , I had originally thought about this i9 X but it seemed too expensive 5 grand for a computer that will be worth 1 grand in a year where I would need two of those 1080 ti's plus I didn't even know how to cool it.

Okay, what 8 Thread Ghz sync with that GTX 1080 Ti, I will put it there. Model Brand EVGA Model 11G-P4-6696-KR Interface Interface PCI Express 3.0 Chipset Chipset Manufacturer NVIDIA GPU Series NVIDIA GeForce GTX 10 Series GPU GeForce GTX 1080 Ti Core Clock 1569 MHz Boost Clock 1683 MHz CUDA Cores 3584 Memory Effective Memory Clock 11016 MHz Memory Size 11GB Memory Interface 352-Bit Memory Type GDDR5X

So does Hyperthreading effect overvoltage. I have never used a hyperthreaded processor, but I have taken this non hyperthreaded one up to screwed up levels for moments on the P67 of like 6.5 GHz with a turbo of 7.0 GHz, so if the Z270 is anything like the P67 it will handle it, but when it hit 99C+ I shut it down instantly, but yes those ASUS boards are solid, where I wouldn't ever keep it at that because you are just asking for trouble with a OC of 1.969 the standard is it unstable, Very! In any case, if you wanna cook a processor take a 3.3 GHz up to 6.5 GHz and keep it there.

It does, the board that will be bought if this works is the one recommended by Intel for OC which supports overclocks and the Turbo, which is the P67 for my current processor, where if it is OC'd to 4.0 GHz it actually runs up to Turbo 4.5 GHz or the Z270 for this one with Overvoltage protection and a safe slot, where this one if non- Overclocked to 4.2 GHz runs at Turbo 4.5 GHz, so with watercooling I think the thermal max is about 6.9 GHz or 7.2 GHz Turbo, but I just want it to sync with the card since that previous one is 3.3 GHz which can go to 5.0 GHz or 5.5 Ghz Turbo, which the highest I would this one to is 5.9 GHz with a 6.2 GHz Turbo, but whatever syncs with that card.

I have often heard that your computer is only as fast as your slowest part what would I need to overclock this processor to, to balance this video card. It has a water-cooler 280mm water-cooler so I don't think temperature will be a issue, but I want them to balance. Processor Video Card Because currently I clock this processor to 4.0 ghz. Current Processor to balance. Current Video Card Which I know is off by 1% , that is due to overheating above that with a standard fan cooler which sits at Min 44 C to Max 87 C which is say below 100 C to 150 C where it melts but I always go below 99 C to be safe which I have been told be be OC'd to 5.0 Ghz with watercooling.