Vmedvil

Yes, but it is in that ds solved form being Laplace prime, XYZ being Laplace that you see.

Yes, it is co-variant my curvature is co-variant why does this matter Co-variant ks2 = K = (1/2)R Co-variant

Ya, Contravariant and covariant are no different, from everything I have looked at.

Well, it has to be uv and not ab has to be up to my standards of a non screwed up equation too, I won't use the ab form.

Oh, I agree, but money is just paper and people kill each-other for it and waste much resources to acquire it. It shows how stupid people really are. If handed a Ruby then next to it the exact value in money then made the person choose between the ruby and the money value of it, the person would always take the money value instead of the Ruby, then I would laugh silly monkey paper and not a physical asset.

Can't beat a Legal virtual money printer. I used to do this on Darkrp servers as mob boss, they would be like you defeated the mayor mob boss Medvil, do you want to be mayor, "Na, guys I will stick here and print money."

Furthermore. Which I using that form. ks = (K(8π/C2)) , K = ((-Duv(g) -ktuv)Tuv-1) ∇'(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,μ,Y,q,a,β) = (((ħ2 /(2Erest/C2)) ∑3a =1 (d2/d((C2/Erest)∑Ni = 1 MiRi)2) + (1/2)∑3a,β = 1 μaβ(Pa - Πa)(Pβ - Πβ) + U - (ħ2/2)∑3N-6s=1(d2/dq2) + V)((|(Log(DgDaDψDφ-W)(((2ħGC2))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμ(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)ψi +(ψ-bar)iLVijφψjr + (aji) - (μ2((φ-Dagger)φ) + λ((φ-Dagger)φ)2)/-(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)2)|)-e2S(r,t)/h)) - ((Erest/C2)ωs((((-Duv(g) -ktuv)Tuv-1)(8π/C2))2)1/2 + (S/ (((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp ))))Rs2/2))) / (ħ2/2(Erest/C2))))1/2(((1-(((2(Erest/C2)G / Rs) - (Isωs((((-Duv(g) -ktuv)Tuv-1)(8π/C2))2)1/2 + (S/(((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp )))))/2(Erest/C2))+ (((8πG/3)((g/(2π)3)∫(((Erelativistic2 - Erest2 / C2) + ((Ar(X) + (ENucleon binding SNF ε0 μ0 /mu) - Ar(XZ±)/Z) / mu)2)(1/2)(1/e((ERelativistic - μchemical)/TMatter)±1)(ħωs + ħωs) - ((ksC2)/ Rs2) + (((((-Duv(g) -ktuv)Tuv-1)(8π/C2))2)1/2(ΔKiloparsec)))2/(C2)))1/2)

And where the Electromagnetic Stress tensor is useless, so That will get reverted again back to ks2 ∇'(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,μ,Y,q,a,β) = (((ħ2 /(2Erest/C2)) ∑3a =1 (d2/d((C2/Erest)∑Ni = 1 MiRi)2) + (1/2)∑3a,β = 1 μaβ(Pa - Πa)(Pβ - Πβ) + U - (ħ2/2)∑3N-6s=1(d2/dq2) + V)((|(Log(DgDaDψDφ-W)(((2ħGC2))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμ(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)ψi +(ψ-bar)iLVijφψjr + (aji) - (μ2((φ-Dagger)φ) + λ((φ-Dagger)φ)2)/-(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)2)|)-e2S(r,t)/h)) - ((Erest/C2)ωs((ks2)1/2 + (S/ (((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp ))))Rs2/2))) / (ħ2/2(Erest/C2))))1/2(((1-(((2(Erest/C2)G / Rs) - (Isωs(ks2)1/2 + (S/(((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp )))))/2(Erest/C2))+ (((8πG/3)((g/(2π)3)∫(((Erelativistic2 - Erest2 / C2) + ((Ar(X) + (ENucleon binding SNF ε0 μ0 /mu) - Ar(XZ±)/Z) / mu)2)(1/2)(1/e((ERelativistic - μchemical)/TMatter)±1)(ħωs + ħωs) - ((ksC2)/ Rs2) + ((ks2)1/2(ΔKiloparsec)))2/(C2)))1/2) has to be uv, ab is useless. Which K goes to Chistoffel symbols which is the wrong direction. So, now I am going to Einstein's Original papers as human hands have corrupted it to see how he did this. 1900-1909 Einstein papers Starting from k Luckily I can read german. 1912-1914 Writing of Einstein Here

Well, I did but it got split.

Whatever that adds more to my case, that being the right form saying Energy stress and Dark Energy. Which I am going to take that part through negative -1, so it flips the signs. ∇'(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,μ,Y,q,a,β) = (((ħ2 /(2Erest/C2)) ∑3a =1 (d2/d((C2/Erest)∑Ni = 1 MiRi)2) + (1/2)∑3a,β = 1 μaβ(Pa - Πa)(Pβ - Πβ) + U - (ħ2/2)∑3N-6s=1(d2/dq2) + V)((|(Log(DgDaDψDφ-W)(((2ħGC2))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμ(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)ψi +(ψ-bar)iLVijφψjr + (aji) - (μ2((φ-Dagger)φ) + λ((φ-Dagger)φ)2)/-(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)2)|)-e2S(r,t)/h)) - ((Erest/C2)ωs(((8πGTab' + Λgab - Rab) * gab-1))1/2 + (S/ (((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp ))))Rs2/2))) / (ħ2/2(Erest/C2))))1/2(((1-(((2(Erest/C2)G / Rs) - (Isωs(((8πGTab' + Λgab - Rab) * gab-1))1/2 + (S/(((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp )))))/2(Erest/C2))+ (((8πG/3)((g/(2π)3)∫(((Erelativistic2 - Erest2 / C2) + ((Ar(X) + (ENucleon binding SNF ε0 μ0 /mu) - Ar(XZ±)/Z) / mu)2)(1/2)(1/e((ERelativistic - μchemical)/TMatter)±1)(ħωs + ħωs) - ((ksC2)/ Rs2) + (((8πGTab' + Λgab - Rab) * gab-1))1/2(ΔKiloparsec)))2/(C2)))1/2)

Well, that is still mainstream just a concept of String Theory and CMB Astrophysicists and the first two laws of thermodynamics, but whatever. Graviton Brane Action NASA Laws of Thermodynamics The Fact there is a Huge Cold spot in the CMB

Okay, I don't see how that changes anything, I used Gaussian Curvature and set it equal to (1/2)R in EFE I didn't go to Tuv but I could have, stopped at Guv Oh, I see what you are whining about that is for gab, which the first time I used for this part. Mordred you caused this to be that way, I changed it because of you from the original form which was gab because I took it on oh Mordred must know what he is talking about but this version is worse. Detransform ∇'(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,μ,Y,q,a,β) = (((ħ2 /(2Erest/C2)) ∑3a =1 (d2/d((C2/Erest)∑Ni = 1 MiRi)2) + (1/2)∑3a,β = 1 μaβ(Pa - Πa)(Pβ - Πβ) + U - (ħ2/2)∑3N-6s=1(d2/dq2) + V)((|(Log(DgDaDψDφ-W)(((2ħGC2))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμ(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)ψi +(ψ-bar)iLVijφψjr + (aji) - (μ2((φ-Dagger)φ) + λ((φ-Dagger)φ)2)/-(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)2)|)-e2S(r,t)/h)) - ((Erest/C2)ωs((1/2)R)1/2 + (S/ (((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp ))))Rs2/2))) / (ħ2/2(Erest/C2))))1/2(((1-(((2(Erest/C2)G / Rs) - (Isωs((1/2)R)1/2 + (S/(((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp )))))/2(Erest/C2))+ (((8πG/3)((g/(2π)3)∫(((Erelativistic2 - Erest2 / C2) + ((Ar(X) + (ENucleon binding SNF ε0 μ0 /mu) - Ar(XZ±)/Z) / mu)2)(1/2)(1/e((ERelativistic - μchemical)/TMatter)±1)(ħωs + ħωs) - ((ksC2)/ Rs2) + ((1/2)R)1/2(ΔKiloparsec)))2/(C2)))1/2) This is gab for Calabi Yau Manifold which this was a String Theory Equation so it is. (1/2)R = ((-8πGTab' - Λgab + Rab) * -gab-1) And I even changed it to inverse matrix instead of 1/gab so you would stop bitch about how I handled EFE even though they are exactly the same matrix. ∇'(x,y,z,t,ωs,ωp,M,I,k,φ,S,X,Z,μ,Y,q,a,β) = (((ħ2 /(2Erest/C2)) ∑3a =1 (d2/d((C2/Erest)∑Ni = 1 MiRi)2) + (1/2)∑3a,β = 1 μaβ(Pa - Πa)(Pβ - Πβ) + U - (ħ2/2)∑3N-6s=1(d2/dq2) + V)((|(Log(DgDaDψDφ-W)(((2ħGC2))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμ(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)ψi +(ψ-bar)iLVijφψjr + (aji) - (μ2((φ-Dagger)φ) + λ((φ-Dagger)φ)2)/-(((Lghost QE - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)2)|)-e2S(r,t)/h)) - ((Erest/C2)ωs(((-8πGTab' - Λgab + Rab) * -gab-1))1/2 + (S/ (((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp ))))Rs2/2))) / (ħ2/2(Erest/C2))))1/2(((1-(((2(Erest/C2)G / Rs) - (Isωs(((-8πGTab' - Λgab + Rab) * -gab-1))1/2 + (S/(((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωp Rp) -ωp )))))/2(Erest/C2))+ (((8πG/3)((g/(2π)3)∫(((Erelativistic2 - Erest2 / C2) + ((Ar(X) + (ENucleon binding SNF ε0 μ0 /mu) - Ar(XZ±)/Z) / mu)2)(1/2)(1/e((ERelativistic - μchemical)/TMatter)±1)(ħωs + ħωs) - ((ksC2)/ Rs2) + (((-8πGTab' - Λgab + Rab) * -gab-1))1/2(ΔKiloparsec)))2/(C2)))1/2)

Oh, I didn't read the rest of the post just the first post by the OP, okay then.

exactly what I said (k2 + m2 )1/2 k2= K = 1/2 R , which then I set equal to that which was already there, It would break dimensional analysis to change it.

that was on the K side and not the matrix side, it was algebra rules until it hit 1/2 R

No, this is all stuff I already knew. You just assumed I was always uneducated on math like Polymath. In Either case, those dimensions are still zero which still = does not exist.

and actually I was wrong about one thing, see I thought it would change guv but it doesn't, it has the same state inverse and normal.

I told you how that works.

Ya, another post made me think about this which applies to this not directly but is a concept that helps my cause that they are infinite in range the WNF and SNF just very small in magnitude, did you know the impedance of a Superconductor is not actually zero but near zero and can be measured by heat released when AC current is run through YBCO. Maybe, the experiments just cannot detect it below that level, Too bad there isn't AC Strong Nuclear Force or Weak Nuclear Force. The Theoretical on that is supposed to be zero but in reality it is not.

Ya, something odd happens when things become superfluidic, they have zero viscosity which is kinda like how a Superconductor has zero resistance which is not actually zero just very close to zero, I did this experiment during college where you run AC current through YBCO a high temperature superconductor and there is still resistance in the form of impedance to some degree which can be measured as near zero but not actually zero, I imagine super-fluids are like that too near zero not zero actually for viscosity. Superfluid Properties video

Use the longer PCR range, I think the fragment was damaged or mutated upon entry personally, also make sure your mRNA was not damaged upon entry, Cas9 will not function if it has mutations or damage in it nor will the mRNA Guide. Both of these are most likely, DNA repair does not work that way that you said only in breaks and crosslinks etc are repaired. check specifically that these both match the actual protein and guide mRNA code exactly and the mRNA for the protein was translated did you put a upstream or downstream promoter on it you may want to if this keeps happening and you find the codes match, exactly for the inserted protein and the actual protein. When checking for Cas9 fragment not the entire Cas9 gene had been inserted: in future we’d test for entire gene using long range PCR If this happens again post something, I have a different way to insert it, that will be quick and easy along with cheap that is not perfect but is more gentle way of insertion than the one that you are using. Sticky Blunt Ends. Though, if you are unlucky or do it wrong it will kill the plant cells used on or damage them enough that they will not grow, but this requires a high speed Centrifuge and two types of protein Endonuclease and ligase, a test tube, and a mutagen chemical along with Polyethylene Gycol 400 which I will outline if it comes to that.

This argument is silly, there is an equation that explains this, exactly, move this to speculations like you do every other post like this.

It is just like the standard model in dunce form.

Here is what I will do, enjoy now plug it all back in. (((1+ (∇'(x',y',z')/∇)2C2)1/2 - (2MbG / Rs) - V)-2Mb)/(ωs1ωs2 ) = Is The first one says they are infinite in range all of them. And the Cross product is never going to happen. I can read my own equation, I don't care if you cannot. Use the dunce hat version then. Luniverse = (∇Charge,∇Color,∇flavour,∇gravity - ∇Dark Energy) charge possible states per point (1,2/3, 1/3, 0,-1/3,-2/3,-1) Color Possible states per point(R,B,G,0,G,B,R) Flavour possible states per point (I,II,III,0,III,II,I) Gravity/Dark Energy possible states per point of space (Energy,Mass,Spin,0,Energy,mass,spin) (Universe Volumetric Planck State @ size of universe in radius) =(3/4)π ((1/(tpC2)) Luniverse RUniverse)3

a) so where the field = -infinity, so it needs to be solved for guv then, which is going to take forever as b) So I would have to do a cross product of every part which it is solved for dot product which would take forever. c) well, that is based on the Mi Ri or MiRi2 terms, which would mean solving for Is which would take forever. cII), is easy as it is just plugging in S terms. well, there is just that one which is when a dimension does not exist, so that is done.