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David_K

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  1. Hey all, it's been awhile on this post, but... I DID get the integral solution discussed above... for anyone interested, it is in the attachment: (I'm not good at entering in lots of math in these threads) I readily admit I did NOT actually come upon this solution through all the hard work it would appear; I found a really cool integral website called integral-calculator.com <---- really good!! if you need an integral. They also have a related site for derivatives. I now have another question I was hoping someone could help with: If we look at this integral solution, it clearly breaks down into 4 separate parts-- two of which are clearly imaginary. and two which appear to have an imaginary term (that imaginary term can actually be totally eliminated, and those roots are real). My question is this: I am guessing these 4 separate parts of this solution might correspond to the 4 quadrants (where the trig function changes sign). If the above guess is correct, is there any way to know which part of the solution corresponds to which quadrant it relates to... ??? If you followed me this far, congratulations, and thanks for your effort. Any ideas ?? integral_solution03.docx
  2. Sorry to hear about your history of potted plants Taeto--lol. And more sorry it wasn't a simple integral I had overlooked. I will have to keep looking.. you could say it's kinda cosmological. Thank you so much for your help... if anyone else can see a better solution, please let me know.
  3. I agree, Nice Taeto. I was looking for an analytical solution though. But nice to see the numerical approach.
  4. Astute observations Taeto... We know that the expression B(k/ r Cos x)2 is always at most =A, and never negative, so that the radical is always real. Does that help?
  5. Hi, Thanks for the quick reply. I think the first expression was changed-- it's not (A - B)(k/cos x)2, but A - B(k/cos x)2 sorry, left out the r -- should be (k/ r Cos x)2 -- Of course that makes little difference.
  6. Hi, I came across this integral doing some research which I could not integrate. May need to do some sort of substitution?? Any help will be appreciated. I have attached a microsoft word document with the integral. Math_Help_Integral.docx
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