bedroomScience

That's what I thought. No CO2 during precipitation or reaction of precipitate means -OH right?

No, gas release from the precipitate. It just turns back into MgSO4.

Wow, completely forgot that I could do that. It's too late, I already have it in electrolysis for a few days now. The Idea was to produce NaOH + PbO2(anode layer). I've had it at 5V, Pb Anode, Cu Cathode (PbO2 layer formed in solution as anticipated). So does not starting with thermal decomposition change the product (IDK, NaCO4 maybe)? The reason I ask is because I reacted it with MgSO4 and it immediately precipitated what appears to be Mg(OH)2. The precipitation was fast, unlike NaHCO3, but there was gas release. So I'm wondering if that's MgCO3

I'm new to chemistry and first I'd like to say, NO, I'm not trying to plate out sodium metal, in an aqueous solution, that's just ridiculous, lol(though I did see something on KOH but the product was less than desirable). I am however trying to knock CO2(g) Off and synth NaOH. Is that even possible? The way I see the reaction carrying out is: NaHCO3 + H2O -> @Anode: CO2(g) + O2(g) + 2H+ , @Cathode: NaOH + H2(g) + OH- Is that correct?