Rebeka

Hello everyone! I was wondering if anyone could show me how the amide on the drug Ibrutinib would react with LiAlH4? I understand how amide would normally react with LiAlH4 but I am confused as to how I would react this amide because of the placement of the N. Any help would be greatly appreciated. Thank you I've attached an image of Ibrutinib so you can see the amide that I am trying to react !

No, it is just for a project to show a possible reaction mechanism to form it.

I have been told the Williamson synthesis would not work to form the ether I need because diphenyl ether is an aryl halogen. Beyond that my understanding of why it will not work its very limited. I know you can form an ether from a benzene ring, but I do not understand how to form an ether with two phenyl/aryl groups as the R groups. Does anyone know the reaction mechanism that I would use to form the ether on Ibrutinib? https://www.youtube.com/watch?v=CnZQiHgnuok I tried using this as a template for the reaction, but I'm honestly not sure if I'm on the right path here

Hello everyone! I was wondering if anyone could help me with a functional group formation and curly arrow mechanism. On the drug Ibrutinib there is what I think is a diphenyl ether. I know that the Williamson Synthesis can be used to form ether but I do not understand how to form a diphenyl ether at all. I tried looking up the Ullmann synthesis but I am not sure if that would be the correct way to form a diphenyl ether. Could anyone please show me how/ what reaction would occur that would form a diphenyl ether on Ibrutinib? Any help or suggestions would be very much appreciated. Thank you! http://www.chemspider.com/Chemical-Structure.26637187.html I have attached an image of Ibrutinib in the URL above