student_lfcs

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Ok. Please see if I am right this time: Total mass =18,000 kg Net force exerted= 40000 - 5000 = 35000 Accelration: 35000 / 18000 = 35 / 18 = 1.95 m/s^2 force exerted by wagon 1 on wagon 2: Accelration x Mass Mass in this case = 4 x 2000 = 8000 kg; Accelration is same i.e. 1.95 m/s^2 So F = 8000 x 1.95 = 15555 N

Ques: An 8000 kg engine pulls the train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 newton and the track offers a frictional force of 5000 newtons then calculate the force of wagon 1 on wagon 2. Ans ( I tried) : Total weight =18,000 kg Net force exerted= 40000 - 5000 = 35000 Accelration: 35000 / 18000 = 35 / 18 = 3.5 m/s^2