Thanks, that looks about right. Looks like 8 equations with 9 unknowns after you throw away the C4 & C5 variables? Is 8 equations with 9 unknowns solvable? I thought you need 9 equations? This is assuming the 3 way equal equation can be arranged into 3 equations:
I think the 3 way equal equations may be reversed in their coefficient though
4(A1 + B1 +C1) = 2(A2 + B2 + C2)
2(A2 + B2 + C2) = (A3 + B3 + C3)
4(A1 + B1 +C1) = (A3 + B3 + C3)
How can you solve 8 equations with 9 unknowns? (A1, A2, A3, B1, B2, B3, C1, C2, C3)
I know from guess and check A1 = 7, A2= 18, A3 = 0, B1 = 26, etc. (and the rest can be filled out), but isn't it strange there are only 8 equations?