sofie

The article can be downloaded from this link: https://www.researchgate.net/publication/333190051_Solvent-mediated_extraction_of_fatty_acids_in_bilayer_oil_paint_models_a_comparative_analysis_of_solvent_application_methods The description is on page 3 under "Simulated cleaning test procedure" I agree that it looks weird. It could be that they are simply referring to 34% and 51% of ethanol in water and not some weight/weight ratio between Evolon and ethanol. I partly came to that conclusion myself but couldn't seem to get the numbers to match. Could it be that the weights listed for Evolon and ethanol are the weights of the individual Evolon strips and the amount of ethanol absorbed into the tissue? So, if I were to try this procedure myself I could soak Evolon tissue in an unspecified amount of ethanol as long as it is 34% or 51%? Thank you for your replies so far!

The article can be downloaded from this link: https://www.researchgate.net/publication/333190051_Solvent-mediated_extraction_of_fatty_acids_in_bilayer_oil_paint_models_a_comparative_analysis_of_solvent_application_methods The description is on page 3 under "Simulated cleaning test procedure" I agree that it looks weird. It could be that they are simply referring to 34% and 51% of ethanol in water and not some weight/weight ratio between Evolon and ethanol. I partly came to that conclusion myself but couldn't seem to get the numbers to match. Could it be that the weights listed for Evolon and ethanol are the weights of the individual Evolon strips and the amount of ethanol absorbed into the tissue? So, if I were to try this procedure myself I could soak Evolon tissue in an unspecified amount of ethanol as long as it is 34% or 51%? Thank you for your replies so far!

I am reading an article for my thesis in paintings conservation and I've come across some calculations that I can't seem to figure out. A type of absorbing tissue called Evolon is supposed to be kept overnight in a sealed container "loaded with ethanol". Strips of Evolon measuring 2 x 5 cm2 are placed in two different containers, one with 34% ethanol (87.4 mg Evolon / 102.7 mg ethanol) and one with 51% ethanol (92.3 mg Evolon / 149.1 mg ethanol). The numbers in the parentheses are given by the authors. I don't see how they relate to the percentage values. Can anyone explain to me how I can calculate the right amount of ethanol to a given amount of Evolon tissue?