insane_alien

no but that doesn't apply, you are trying to get the weight in grams, so however many cm^3 of water it displaces is how many grams it weighs.

perfect gas equations is a good start. thats how that law is derived. though with the compressibility factor it skews it though,

or not

side side side side note(this is getting ridiculous): diamond electronic devices are a result of doping ala silicon electronic devices. diamond is capable of acting as a semiconductor.

guided missiles...

side note: This is the graphite form of carbon, the rarer and more expensive type(diamond) bonds to 4 other carbons and doesn't have any free electrons.

depends on the flame really. you can get a cold blue flame which is too cold to glow blue but it does anyway because of electron interactions. that one is definitely a plasma. in a candle flame it is a plasma because if you actually look at a cross section it is perfectly transparent in the middle(where it would be hottest) and only around a 1mm thickness glows. this is where the plasma exists. i can't remember the exact temperature at which air goes opaque but i think it is up there at 3000K

appart from the link completely failing to work, we know that newtons 'laws' are wrong. this is why to be perfectly accurate you should use einsteinian mechanics.

yeah but usually once you see it it is already too late to do anything about it.

but remove the air resistance and they drop at the same rate. reality is under no such restraints as 'intuitiveness'.

bombs in a crowded place are never a good idea. at best, no one will be hurt and you'll be arrested. at worst, someone will be injured, you'll be arrested and be spending some time hoping to god you don't drop the soap.

to expand on what iNow is saying, a plasma is a charged gas. that is to say, not all the electrons are bonded to the atoms. this causes a lot of light to be emitted as electrons rejoin the charged atoms as they cool down. in a normal candle flame this happens to be in the visile range but this is not always the case and you can have an invisible flame.

the wavelengths of the electrons do not affect the absorbtion of a photon(at least not in the way you think) it is the energy gap between orbitals. if this energy difference correponds to the energy of the photon it can be absorbed by the electron. if not then the photon will not be absorbed.

can you show us the working you have already done? seeing as it is a perfect gas you'll want to muck around with the perfect gas equation PV=nRT n and R are constant in this case

it'll have to be 6 million light years tall then so said tiny penis is visible then(with an electron microscope of course).

yeah, we've been over that one several times on this forum already. we deduced it was physically impossible then, we would reach the same conclusion now.

just think of it as smell-o-vision

making your own instrumentation is probably about the cheapest way to do it. another way is water displacement. you have a glass(modify this for whatever size you need) full to the brim of water, a small floatingcontainer to hold your sample(make sure it will float WITH the sample in it) and something that can measure volume(a measuring cylinder, jug, what ever, i've even calibrated pint glass for similar purposes). fill the big glass with water, place the sample container in gently(so as not to spill more water than it takes) then put the measureing device under the big glass. add your sample to the sample container and collect all the water that runs off. every cubic centimeter is roughly a gram(IS a gram if you do it a 25*C)

also, isn't this the method they use to remotely detect atmospheric compositions on other planets. i was thinking that if it worked on a large thickness of air, it might be possible to do the same on a small thickness of air but with more sensitive equipment.

i think martin meant omega = to 1 rather than 0 if omega is less than one it corresponds to negative curvature(whatever that means)

sure seemed that way with the thread title and all you don't need to be. and those devices emit a whole gamut of signals, theres microwaves for wi-fi and bluetooth, IR for IR comunications and such. now, the recievers for these signals won't pick up waves outside the range they were designed for(well, they will but the signal will be incredibly tiny) and microwaves, well, they are really far away from blue light on the spectrum. so there won't be much interference there(especially since the antenna and that are usually encased in plastic which would block out blue light anyway. so we're left with IR communications, thats much closer to blue light and works on photodiodes(or similar) whch can be affected by blue light. now, if you look at the port for one of these you will see that it is a really really dark red colour(looks black except when there is extreme lighting conditions, i have one here and you can just tell it's red if you look at the sun through it.) this also filters out blue light but lets IR pass by easily. so, to get any reasonable interference you will need an ultra exposed reciever or incredibly intense blue light(probably enough to melt the device anyway) to get interference on an IR device and for a microwave transmission, well, your going to vapourise the device before you get interference unless you stick it near a microwave transmitter.

and it would still be a rip off of existing designs.

not always, stack two boxes on top of each other. push the bottom one. there is friction between the top and bottom boxes but it acts in the direction of motion.

theres no force causing that. you might want to look up 'momentum' and newtons laws of motion.

provides a physical barrier, the caustic forms an iron compound a few moleculse thick on the surface. the oxygen can't get to it but the voltage required to overcome this is non existant. if you scratch it it will still rust.