Thank you for replying!
I think that I already have the empirical formula for dichromate but all I've got so far is this:
K2CrO7 + Fe(NO3)2
I tried to search up what acidified dichromate means but I couldn't find anything, does it just mean I add H+
And then I have no clue how to know which part of it will go through reduction and which will go through oxidisation. For example, a previous question in the booklet asked the same question, except it had the balanced equation given to me of:
5Fe{2+} + MnO4{-} + 8H{+} --> 5Fe{3+} + Mn{2+} + 4H2O
So I knew that the oxidation was where electrons were lost, which was:
5Fe{2+} --> 5Fe{3+} + 5e
and the reduction was where electrons were gained, which was:
MnO4{-} + 8H{+} + 5e --> Mn{2+} + 4H2O
So if I knew the whole equation I would know how to write out each half equation, so really my question is how do I do my question I posted without knowing the equation and if there is a way I'm meant to get or know the equation?