HbWhi5F
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Posts posted by HbWhi5F
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@studiot In Symmetric difference why is intersection of 3 not included, also what its associative.
Symmetric difference means "unique to" ? So AΔBΔC != (AΔB)ΔC
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@Genady Explain
this doesn't makes sense to me. This implies if x doesnt belong to intersection of 3 sets that means it doesn't blong to any set. -
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Edited by HbWhi5F
This doesn't makes sense
If x e (A1 n A2 n 143 n ... ) then x is not the element of at least one of the sets.
This implies if x doesnt belong to intersection of 3 sets that means it doesn't blong to any set.
De Morgan's Law
I think this is false when C⊂B with elements of A U B
If A A B = A A C, then B
similar to
Symmetric difference with 3 sets
In Symmetric difference why is intersection of 3 not included, also what its associative.
Symmetric difference means "unique to" ? So AΔBΔC != (AΔB)ΔC
Cardinal Number of set Union of 4 Sets
I thinkg it should be - n(AUBUCUD)
= [Sum of number of elements in sets A, B, C and D]
- [Sum of number of elements of intersection of sets taken 2 at a time]
- [Sum of no. of elements of intersection of sets taken 3 at a time]
- Elements of intersection of all sets
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Edited by HbWhi5F
It breaks the rule number of elements of a powerset of Set A = 2^n . Also contradicts null set is a subset of everyset. Also some places it says ∅ is a element of every set
2^4 = 16, but my results say 39
Example for set {1,2,3,4}
There can be 5 no. of sets n+1
single element = n
2 element = 10 - {1,2} {1,3} {1,4} {2,3} {2,4} {3,4} {1,∅} {2,∅} (3,∅) (4,∅)
3 elements = 10
4 elemets = 4 =>{1,2,3,4} {1,2,3,∅} {1,2,∅,4} {1,∅,3,4} {∅,2,3,4}
5 element = 5
additional the ∅
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What I do
I give it pdfs and a long instruction, and then ask questions.
Best Service and Local LLM
I use ChatGPT, should I switch to something else or something local ?
Give AI access to screen, able Point-&-Ask while reading ?
I saw video people doing similar things w/ Gemini, Claude.
1. I may use local OCR/CV and send it to LLM as text.
2. and use local Speech to text ?
Should I give ChatGPT access to local files for this purpose
LangChain - TechLinked - https://www.youtube.com/watch?v=9AXP7tCI9PI
Local LLM Retraining, RAG, Context Docs - https://www.youtube.com/watch?v=fFgyOucIFuk
How else can I use AI to study ?
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@KJW What is that have to do with ?
I meant Normal = Calculated and Observed=Abnormal (has the definition below it says)
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Given:
p°A = 450 mm Hg (pure component's vapour pressure), °B = 700 mm Hg, = 600 mm Hg
Let xA and xB are mole ractions, So xB = 1 − xA
Using Raoult’s law: Total Vapor pressure = mole fraction of component A in it's vapour and liquid phase times the Vapour pressure of pure component A + same thing for B
P = xA·p°A + xB·p°B
600 = 450xA + 700(1 − xA)
600 = 700 − 250xA
xA = 0.40
xB = 1-.4 = 0.60
Partial vapour pressures:
pA=pA^0 * xA (Parital pressure of a component = vapoyr pressure of pre component times it's mole fraction)
pA = xA·p°A = 0.40 × 450 = 180 mm Hg
pB = xB·p°B = 0.60 × 700 = 420 mm Hg
pA and pB are vapour partial pressure, ie the pressure exerted by them on solution
Vapour phase composition:
pi = yi * P (partial pressure of a component = the ratio of it's vapour phase the vapour phase of the other component) times the total vapour pressure on solution
yi=pi/P
yA = pA / P = 180 / 600 = 0.30
yB = pB / P = 420 / 600 = 0.70
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Edited by HbWhi5F
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Edited by HbWhi5F
@exchemist Given the context of the question AI is right but If I got the definattion right, it is not possible to be get the value (from the infomation in the book). Either I got the question wrong or the definetion.
Ok the conceptual problem is -
We got ratio amongst vapours
and ratios of the components amonst their phases
How are they connected ?
It should be something like -
Let V and L be phase of Vapour and LIquid in the solution
V/L = [1/Q1] / [(xA/y1) + (xB/y2)]/Q2
Q is some ratio to normalize the value from 1 to a fraction of the solution - it should be y1+y2/xa+xb
V/L=[1/(y1+y2/xa+xb)] / [(xA/y1) + (xB/y2)]/(y1+y2/xa+xb)
V/L=[1*xa+xb/y1+y2] / [(xA*y2+xB+y1/y1y2) / (y1+y2/xa+xb)]
0.30+0.70/L=xA + xB
1/L = 0.40+0.60
1/L=1
L=1/1
V/L=ya/xa
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xA and xB are mole fractions of each components - Vapour-liquid phase ? why is AI saying it's liquid phase composition ?
Henry's Law : p = KH x “partial pressure of as in vapour phase (p) is proportional to ole fraction of gas (x) in solution” and is expressed as:
Raoult’s Law: A=xA pA∘
pi = yi P total - this is the ratio of 2 components in vapour phase
AI Solved -
Given: p°A = 450 mm Hg p°B = 700 mm Hg Total vapour pressure, P = 600 mm Hg Let xA be the mole fraction of A in the liquid phase. Then xB = 1 − xA Using Raoult’s law: P = xA·p°A + xB·p°B 600 = 450xA + 700(1 − xA) 600 = 700 − 250xA xA = 0.40 Therefore: xA = 0.40 xB = 0.60 Partial vapour pressures: pA = xA·p°A = 0.40 × 450 = 180 mm Hg pB = xB·p°B = 0.60 × 700 = 420 mm Hg Vapour phase composition: yA = pA / P = 180 / 600 = 0.30 yB = pB / P = 420 / 600 = 0.70 Final Answer: Liquid phase composition: xA = 0.40 xB = 0.60 Vapour phase composition: yA = 0.30 yB = 0.70
≤ can mean- till it or till it OR infinity ?
in Homework Help
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Edited by HbWhi5F
equalto /greater than OR greater than /equal to
Contextually I understand why it's (0,infinity) but > w/ dash under as 2 means aka till it and till it or infinity
x≤1/2 can mean (0,1/2) or (1/2,infinity)