novice1964

Hi, I though the calculation was simply:- sum a = (49/6)*(48/5)*(47/4) = 921.2 because you have 6 chances to match the first number 5 chances to match the second number 4 chances to match the third number but I am not sure how the next bit work you have six numbers on the ticket so does that mean you have to involve sum b = (6/3)*(5/2)*(4/1) = 20 some where possibly sum a/sum b? so you get 961.2/20 = 48.06 or does it mean you have to buy 922 tickets to guarantee a win of £10.00 with twenty chances on each ticket???? or should it be sum c (49/3)*(48/2)*(47/1) =18424 then 18424/20 = 921.2 ?????? ?????????