Hi,
I though the calculation was simply:-
sum a = (49/6)*(48/5)*(47/4) = 921.2
because you have
6 chances to match the first number
5 chances to match the second number
4 chances to match the third number
but I am not sure how the next bit work
you have six numbers on the ticket so does that mean you have to involve
sum b = (6/3)*(5/2)*(4/1) = 20
some where possibly sum a/sum b?
so you get 961.2/20 = 48.06
or does it mean you have to buy 922 tickets to guarantee a win of £10.00 with twenty chances on each ticket????
or
should it be
sum c (49/3)*(48/2)*(47/1) =18424
then 18424/20 = 921.2 ??????
?????????
