Caleb

That would be the Coran (Koran?) I believe.

I am a Latter Day Saint. We believe that women should be treated with upmost respect. Women are not worshiped, but highly respected. Because men in my religion hold the presthood (considered God's power) and women can't, we need to serve everyone. I am not saying that only women should be treated with respect, but everyone. Its just that when you hurt a woman, it is considered a more grevious sin than if you hurt another man.

I would recommend reading the Book of Mormon. Its like the bible except its location is in the America's instead of Europe.

Well everyone, I was able to get some pottasium permanganate just as I was leaving for camp from a good friend. I got first place in the fire building compitition . Thanks for giving me the great idea!

Yes, that's what I mean. Merged post follows: Consecutive posts mergedI cannot get any pottasium permanganate at a chemistry store. Are there any disinfectant brands I can buy at Wal-Mart that will do?

That seems great! Can I just throw the products away or do I need to disspose of them spiecally?

That sounds like something I could use. Thanks for the suggestion. Btw, everything I come up with will be checked by adults. So I'm not going to try it out in the woods all alone, there will be adults there supervising everything. Merged post follows: Consecutive posts mergedJust one more quetion. What are the products of this reaction? Thanks a million!

This Saturday I am going on a one week campout. Due to fire hazards, we are not allowed to bring any fireworks to the campout on the 4th of July. But, since it will be the fourth, the scout leaders have said that we will have a contest to see who can build a fire in the most creative way. But the conditions are: 1. It cannot be explosive 2. It cannot create any hazardous materials such as chlorine or molten iron. 3. You have to be able to buy the ingredients from a local walk-in store. Is there any fun experiments that make fire that I could use? Btw, it would help if I could get some idea's before this Saturday. Thanks a million.

1. Horza2002 2. 3. iNow 4. 5. Rigney 6. YdoaP's

1. Is the equation not true? How is NaOH produced commertially then? I am willing to learn. 2. "General Chemistry by Whitten and Gailey" Chapter 11-8 states: Volatile Acids. Small quantities of the hydrogen halides (their solutions are called hydrogalic acids) are usually prepared by dropping concentrated non-volatile acids onto the appropriate salts. The reactions of cooncentrated (98%) sulfuric acid with solid sodium fluoride and sodium chloride evolve heat and produce gaseous hydrogen fluoride and hydrogen chloride, as the following equations show: H2SO4 (l) + NaF (s) => NaHSO4 (s) + HF (g) H2SO4 (l) + NaCl (s) => NaHSO4 (s) + HCl (g) Like I said before, I do not know for sure if this can be done with bases or not. But it is not rubbish that they can do that with acids and salts. And it was my mistake in the first post, I meant sulfuric acid and not nitric acid. Merged post follows: Consecutive posts mergedI have been studying about NaOH. It turns out that you were right about Na2O not being produced commertailly. However, the equation still turns out. It is produced commertially by electrolisis of NaCl in an aqeous solution: 2NaCl + 2H2O => 2NaOH + H2 + Cl2

I know that NaOH is produced commertially by putting Na2O into water, by the following equation: Na2O (s) + H2O (l) => 2NaOH Oxides of metals are called basic anhydrides because many of them react with water to form bases. Metal oxides that are soluble in water react to produce the corrisponding hydroxides. So you can do this with most other metals, espectally the alkali and alkaline earth metals. I know there is a way to create acids by using other acids and the desired acids corrisponding salt. HNO3 + NaCl => NaNO3 + HCl I do not know if the same principle applie to bases too. But I would think it would go something like this: BaOH + NaCl => NaOH + BaCl I don't know for sure, but this is how I would think it would happen. I hope this helps.

The definition of an oxidation number according to "General Chemistry" by Whitten and Gailey states: Quote - "The oxidation number or oxidation state of an element is the number of electrons gained or lost by an atom of that element when it forms an ionic compound. In covalent compounds... In such cases positive and negative oxidation numbers indicat shifts (not transfers) of electron density from one atom toward another. The more electronegative element is assigned a negitive oxidation number, while the less electronegative element is assigned a positive oxidation number." As an example: Fluorine has an electronegitivty of 4.0 Phosphorous has an electronegitivity of 2.1 The differance is roughly two. So, the electronegitivities are far enough apart for F to "max out" the P. Because F wants the electrons so bad, it will try to make P as positive as possible. But if you take a lower halogen, like Iodine with a electronegitivity of 2.5 and react it with P, you get phosphorous triiodide instead (PI3) or diphosphorus tetraiodide (P2I4) instead of phosphorous pentaiodide (PI5), which is possible but rare. (According to wikipedia, under Phosphorus triiodide) What I want to know is, is there a way to calculate or generalize what oxidation number a compound will use under "normal" conditions. What I mean by normal is, not something like creating some nearly impossible compound at 100,000 atm and at 100,000^50 K. As close to normal pressure and temperature.

I have been reading in my chemistry book about oxidation numbers. For the elements that have several oxidation numbers, how can you predict which one it will use? I know it has something to do with the difference of the electronegitivities between the elements, for example: Since Nitrogen has a higher electronegitivity than hydrogen, the nitrogen atom will gain a negitive oxidation number and the hydrogen will gain a positive oxidation number. Since the electronegitivities are far enough apart, nitrogen can assume its highest negitive oxidation number, which happens to be -3. So in order for the sum of the oxidation numbers of the elements to equal zero, there must be three hydrogen bonded with the nitrogen. Thus creating ammonia. How can you tell if the electronegitivities are "far enough apart" to get the desired oxidation number? Merged post follows: Consecutive posts mergedWhen does the electronegitivity differance start making compouds ionic?

Okay, thanks.

If you knew what the molecular structure of C2H6O is, then could you predict it?