take [0,L] == the bus, and suposse that you are sit in x=x0. the expectation of injury in that place is int_0^L D(x,x0)P(x) dx... P(x) is the pdf of the bomber-location (uniform by hipotesis) then E(x0)=1/L int_0^L D(x,x0) dx.
D_x0 > 0 if x0<x and D_x0 < 0 if x0 >x then by simmetry
E'(x0) = 0 when x0 is in the middle but in that case E(x0) is maximized.
in fact, D_x0x0 is always negative because its more dangerous if x0->x
Then, the solution its seem to be x0 =0 & x0=L