Kedas

All of them

Getting colder isn't realized by making The vibrations stop by some force or anything it is just a result of decreasing the amount of energy and if you are in space (without shielding) you are just a fountain of energy in all directions. You can ask a comet how he/she feels about being in space and doing a close pass around the sun. Space suits don't only isolate so it would be nice and warm inside but also prorect them from all the harmfull radiation in space.

The speed by which the energy flows away from your body is directly related to the temp difference.

I don't think the brain is capable of calculating that but I will play the devils advocate. How do you know your brain isn't calculatiing it if you only see/realize the end result?? I do think that the basic calculations of the brain are derivatives. YT2095 wrote: lying there doing notting, 99$ time, just entertainment value. all this in the same sentence. You are lucky that blike didn't kick you from the forum well, maybe you meant 99%

I think the key in such sort of 'deja-vu' things is the amount of data that is used to store an event. example: If you use very little data to define/recognise a face it is statistically easier to have the feeling that you saw that face before.

What you calculate is only based a mathematical representation, you should useally always believe what you read on your measuring device. I did draw your graph and I see that the internal resistance of the solar-cell isn't constant. I did some checking because I have no experiance with solar-cells and your graph is correct. Now the question is which resistor does have the max power well that is where Rload=Rinternal and that is where the curve/line changes direction that is in your case around 220ohm. for Rloads above 220ohm the solar cell has a small internal resistance, for values below 220ohm the solar cell will have a high internal resistance. The slope of your curve defines the value of the internal resistance. So forget about the values that cross the axis because that is only valid when the internal resistance is constant. (you can use that methode if you don't mix the values above and below 220ohm)

For example could you be doing an scientific experiment in your dream and get a result although you didn't know that result when you went to sleep. Also why can't we find/remember this data. example: you can dream about: waving hair in the wind stars in the night sky. glass scattering walking in sand etc. It will al be believable represented. But if you ask someone that is awake to describe such event they usually are very poorly not even taking natures laws in account. How much is a dream like a movie playing and how much is it really 'calculating' based on laws. Is my brain powerfull enough to calculate waving hair in the wind? This raises an other question how fast is time going during your dream? is 1min. real time about 6sec dream time? so the brain has time to calculate everything? Something else: pinching your arm to know if you are awake or not is a myth that isn't true. I tested it you just feel the pain and the dream goes on. Why is it so hard to stay in the dream when you start to realize that it is a dream? Well this message is much longer than what I planned, sorry about that.

Yes, but 5.43V/12ohm = 0.4525A not 0.063A meaning that that line you drew isn't going through that point ?? how many points did you have and could you more or less connect them with a straight line? maybe could you just give me all your measuring points? R= V= I= R= V= I= etc.

with Y=EMF-X.r I mean X is the current through the resistor. Y is the voltage over it. VT=23.547 - 287.59 * I VT = voltage over the resistor I = current through the resistor. example: your current is 0.02A Then your voltage is about 17.8V (assuming that the values that you give are correct) your equation y=-287.59+23.547x doesn't make much sense.

VT = -2.21 EXP-4 = -0.000221Volt it isn't zero because you rounded the value of the resistor. Are you sure you had 23.54V what was it when you just measured the voltage on the solar-cell without resistor. BTW the equation VT=EMF-I.r is the mathematical representation of that line you drew. Y=EMF-X.r

You will also have to bring the internal resistance of the ampere-meter into account. To check measure the voltage before and after the ampere-meter. Also try to be clear if you give a formula. use an . or * like Vt=EMF-I.r what are the values that you have to determine the internal resistance? (values that cross the axis)

Well I think there should be a difference but if the temp rise of one is 1°C then you shouldn't expect that 4 will get you 4°C. Because it stops rising because the energy supplied is equal to the energy that is flowing away and the higher the temp the easier energy will flow away. also how much energy is reflected and how much absorbed will also depend on the frequency and material.

of course, everything I said is only valid when the energy source (light) is constant.

NASA plans to crash its $1.5 billion Galileo spacecraft into Jupiter next weekend to make sure it doesn't accidentally contaminate the planet's ice-covered moon Europa with bacteria from Earth. http://www.cnn.com/2003/TECH/space/09/14/galileo.ap/index.html

1) Power = current * voltage. 2) theoretically if you make a graph voltage-current and you put all your resistor measuring points on it then you draw a line trough those point. that line will cross the voltage and current axis. if you take tose two values then you have Rinternal= voltage/current The voltage should be the voltage that you measure without resistor attached, the current should be the current when you short-circuit the the power-cell. 3) The Rload power is at his highest when Rload = Rinternal. I can prove that but then you will have to pay me. LOL I have a feeling I'm doing your homework ?

http://www.space.com/businesstechnology/technology/space_elevator_030917.html Nasa is really thinking of building one. When will it be build ?: I was just thinking won't they have a lightning problem ??? What about the static differences in the air, where is the current going to go? found the answer: "what about lightning? The tether would need a pretty thick ground wire to avoid being vaporized during a lightning strike. I guess a ground wire might only need to go up to abot 40,000 feet or so. I assume there wouldn't be a problem with lightning once above cloud level. Maybe have helium balloons at lower altitudes where lightning is a possibility and hydrogen balloons at higher altitudes."

It looks all like playing with mathematics without a real meaning whatsoever. anyone that can see something usefull in it ?? explain. I can't.

yeah, try to find a forum that doesn't have that piece of text. It did spread faster than a virus.

Yes, I got the same but it can be done more simple: 'Get more' symbols isn't working for me so it will have to be this way: m.g = m.v.v / r and v= w.r g = w.w.r.r/r (omega=w=2.pi.f) f = sqrt(g/r) / (2.pi) = 0.00019728 times/sec T = 1/f = 5068.8 sec = 1.41hours or 24h/1.4h =17 times faster. like you see it is mass independant. edit: add on 0.3442 * COS(latitude) * COS(latitude) = percentage that you weight less due to earths rotation. That number is w.w.r/g*100 or 1/(17*17)*100

Yes it is different but marginal De mass is obvious the same but it weights a little less. you can find the formula here: http://hyperphysics.phy-astr.gsu.edu/hbase/cf.html#cf If you can't figure it out I will post it later.

It would make more sense if "never" is removed from the sentence. I mean: can never --> can't

I tried that in netscape and I got: Gateway Timeout The following error occurred: Server unreachable Please contact the administrator.

http://www.theinquirer.net/?article=11567 They claim that they can make an 55W and 30W Opteron next year. I think AMD found the key to a low power CPU and Intel is still searching. edit: Seems they are only talking about their more expensive low-power CPU not the desktop CPU's http://www.amd.com/us-en/Corporate/VirtualPressRoom/0,,51_104_543~74739,00.html.

Lets say seen from a third observer that has little influence of the black hole gravity. 3 persons: - one stays at his location no acelerations. - one goes to a nearby black hole and stays there for a while. - the other one is going at almost light speed away. then they both return to the one observer. What are their individual clocks now if they compare.

That is because correct writing is directly linked with intelligence by most people. If you write an error somewhere people think immediately that you are stupid. Although in practice it are two separate things. But I guess the probability is higher for getting an intelligent person if you take the second one. on the other hand who doesn't want 'god' at his side.