sxandr6

Hey everyone, thanks for the information, it's much appreciated.

So I'm looking a my school schedule for next semester and have been toying with the idea of becoming a chemical engineer, but I really don't know very much about it. So I'm thinking that I'll take intro to chemistry but the only way it'll fit into my schedule is taking it online. I'm kind of worried that it's a class that really should be taken in a class room. Should I wait, or is taking it online not going to be that bad? Thoughts.

Ok I graphed it and found the answer, but where did the 1/2 come from. Is it a property of the cosh.

Nope, sorry not that far either. I might just ask the teacher when I see him next. It's not due for a little while.

Yeah, I didn't think that was right. But the explanation above is over my head. I'm only in college algebra. I thought squaring both sides would work because the back of the book give 2 answers: -1.567 and 1.567.

no, I tried: Ln e^x + Ln e^-x= Ln 5 and then the Ln e = 1 so there for x-x= Ln 5. But I don't think that's right.

e^x+e^-x=5 When I first tried to solve this I tried to take the natural log but that ends up cancelling the x's out. Then I tried to square both sides but I think I messed up squaring the left half of the equation. I ended up with: e^2x+e^x+2e=25. Thoughts?

But wouldn't that elminate the y's. y-y= 3x+4/x Merged post follows: Consecutive posts mergedoh wait nevermind I got it, thanks for your help.

f(x)=x + 4 .......x - 3 I know I need to change f(x) to y and then switch x and y. I got that far I tried to multiply both sides by (y-3) in order to solve for y, but after that I got a little lost.