JPtux

I copied it exactly as it is.

That is pretty much what I did. You have to remember that the 5" ray is impossible in the plane that is 6" away from P. Furthermore, there would be 6 planes, the ones that you mentioned, and the ones on the opposite side of P.

Okay, I have a math question that I would like help with. My teacher and I are unable to solve this problem for some reason: In 3-dimensional space line m intersect plane P in point T, and m is perpendicular to P. The points in space which are 2 inches or 4 inches or 6 inches from plane P are also 5 inches or 7 inches or 9 inches from point T lie on circles. Find the sum of the squares of the radius lengths of the circles. Our answer is 616 but the answer is supposed to be 596. Can anyone solve this? P.S. I'm sorry if I posted this in the wrong forum, I'm new. NOTE: Not a HW problem. Thanks in advance!