It is not what, Mr. Skeptic ?
Not a heat pump ? What do you mean, there is no heat sink ?
When you create a cold, such as in a refrigerator, and you pull the plug of the refrigerator, keeping the door closed, what happens to the air inside the refrigerator ?
1. Does the outside air drop in temperature, to finally meet the temperature inside the refrigerator ?
2. Or does the air inside the refrigerator move up in temperature to finally reach the temperature of the surrounding air ?
I say that it is the second version, which is correct. In a heat pump, a cold is created inside the nitrogen circuit (usually in the range of -15 C). The outside air (usually at -5 C in a cold environment) is sucked through the heat exchanger and what happens ?
The air is dropping in temperature inside the heat exchanger and then, when it comes out, it rises in temperature again, as it is blown away into nature. And what happens to the nitrogen, which was brought to -15C in the circuit ? Its temperature rises back to -5C, the same temperature as the outside temperature.
So here you have an example of the temperature of the gas in the closed circuit "rising spontaneously" to the surrounding air temperature.
What you are saying in your text is that a heat pump cannot work. But indeed it does. Unless you have a different explanation on how a heat pump works ?
I say that if you pull the plug of a refrigerator, the air inside the refrigerator rises back to the outside temperature. A small portion of the air in contact outside the refrigerator might drop in temperature (due to the exchange), but that air is blown away and ultimately will rise back in temperature to the surrounding original temperature.
What you are saying goes against the heat pump...
http://en.wikipedia.org/wiki/Heat_pump