stephen

Thankyou for your help i now know how to get f. However i was wondering if i mirrored the diagram (so i reversed the incline slope etc.) would the resolvents of force be the same as before?

Right i cant upload the rest of the question so ill write it out Continued Fcos30 - 50 x sin30 = 1/3 (50cos30 + f sin30) 0.866 f -25 = 14.43 + 0.1667 f f = 56.3 N The force required to just move the block in the direction shown is 56.3 N Any help will be much apreciated. Stephen Merged post follows: Consecutive posts mergedi follow it up to the last bit but then the answer throws me ? As i wrote it goes from 0.866f -25 = 14.43 + 0.1667f and somehow the above = 56.3 N??

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Hi, I have a worked example of a question to do with forces and i just cant work how he gets to the answer? could you help me? i will upload the example Thanks