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Very clever. I never thought of appointing the 1 km north as 1 unit up on the y-axis. Another question: If 50% of P equals 20% of Q, then P, as a percent of Q, is ? 0.5x = o.2y doesn't seem to fit the question.

I have another question: Sam bicycles at 16 km/h and Chris bicycles at 24 km/h. At noon, Sam is 1 km north of Chris, and each begins to ride north. How many minutes will it take for Chris to catch Sam? I have no idea what to do. I assume using displacement formula or something?

OK, I understand abit of what the question is implying. Say, TD, how did you figure out the answer? Can you please explain it clearly.

Pardon Me

But if you input the "0" in [math]5x + 2 = 0[/math], therefore [math]5(0) + 2[/math] would be 2?

Also, are you using induction method to prove Fermat's last theorem? Where you do this: 1) Show it's true for n=1 2) Assume it's true for n=k, kEN 3) Prove it's true for n=k+1 Is this what you're doing?

Yeah I guess you could do it in your head such as [math]18 \cdot \frac{2}{3}[/math] is simply 12. I approached another question that do not have the answers that I found in its multiple choice. If [math](x-4)(5x+2) = 0[/math], then the two possible values of [math]5x + 2[/math] are: (A) -4 and 2/5 (B) 0 and -18 © 0 and 22 (D) 0 and 4 (E) 4 and 22 At first, I thought okay, then I got x to be simply 0 and [math]\frac{-2}{5}[/math], but as I scrolled through the answer, its not there. I was thinking, okay? Next, I used the quadratic formula for the whole equation which comes to be [math]5x^{2} - 18x - 8[/math]. It yielded 4 and [math]\frac{-1}{4}[/math], but it is for the whole equation, not just [math]5x + 2[/math] itself. Again, I looked at the choices, and none are there. Any help?

I wonder if its poisionous tentacles are strong enough to kill a human? Because I picked up a jellyfish in PEI (Prince Edward Island located in Canada) one time before, and when you touch its bottom it stings. But if you touch its top, it doesn't hurt. Imagine that..

From now on, I will use this thread to inquire my math questions that I have. I don't want to create a new thread for everytime when I have a single, small math question. Waste of time in my opinion. Also, to let everybody know, those math questions will never be my homework. They are just some bogus math questions that I see around or on the Internet. IT'S NOT MY HOMEWORK. Awhile ago, I just found this old Fermat Competition booklet in my bedroom that I entered last year (A Canadian National Math Contest), and I have this question. When [math]a=\frac{1}{2}[/math] and [math]b=\frac{2}{3}[/math], what what does [math]\frac{6a + 18b}{12a + 6b}[/math] equals? I found the answer to be [math]\frac{3}{2}[/math] or rather [math]1.5[/math]. I know this is a really simple question, but I was just wondering how I can find the answer quickly? By using fraction reduction, or substution, or anything that can give me the answer quickly, rather than do all the work necessary.

Are you talking about multiple angle identities? [math]sin(A+B) = sinAcosB + sinBcosA[/math] Also, the question about what is "p and q". They are just a variable for the value of the answer when you put it in the orginal exponent form. i.e. [math]log_{2}p = 3[/math] intends [math]2^{3}=p[/math] and the value of "p" is 8.

I don't think you can lick your elbow even if it rotates 360 degrees because your bone (not forearm.. I don't know the name) in your arm, will disallow that.

Ok JustStuit, I'll fix your Latex mistakes, so other people can read the solution. The quadratic equation is: [math]x^{2} - 100x + 2400[/math] Using the quadratic formula: [math]\frac{-100 \pm \sqrt{10,000 - 4(1)(2400)}}{2}[/math] It will yield: [math]50 \pm 10[/math] Therefore [math]40[/math] and [math] 60.[/math]

Right, I got it. You used the method of substitution.

I can't figure out how to do this algerbically, though I know the answer: There are 2 numbers that their sum is 100; and the product of the number is 24 times 100. The answers are 40 and 60. I have 2 equations: [math]x + y = 100[/math] and [math]xy=2400[/math], but I'm not exactly sure how to put it together and get the answers. Can anybody help me?

An advice: Use latex next time. You are putting us into confusion easily.

Or you can use n*Hc = C(delta)t.

Also Tartaglia , how did you factor it? Can we figure it our by our own hands, not gadgets please?

Nope, it's not homework at all. I was just challenging myself. Relative to this thread: http://www.scienceforums.net/forums/showthread.php?t=17549. See the big crazy formula and the simple formula? I was just trying to factor the big formula and see if it would arrive to the small formula. That's all.

I think there's some missing information, because I tried to use n*Hc = m*c*(delta)t and I can't figure out the (n)?

How did you do that Quantasm? And if possible use Latex please, because I want to avoid confusion.

I am wondering if anyone could factor this for me? [math]a^{4} + 2b^{4} + c^{4} - 2a^{2}c^{2} - 2a^{2}b^{2} + 2b^{2}c^{2}[/math]

I don't know if this will help: [math]cot^{2}x = \frac{cos^{2}x}{sin^{2}x}[/math] or [math]\frac{csc^{2}x}{sec^{2}x}[/math] or [math]cot^{2}x = 1 + tan^{2}x[/math].

I think conductors have higher specific heat capacity because the higher it is, the more energy it lets go thus good conducting. (As in an exothermic chemical reaction). But 5614's reply might make my statements wrong. Or your (victoriangal's is just trying to fool you.

Would 1,2,3-propantriol be acceptable too?

What's "E1" and "SN1"? I apologize, but I only know basic organic chemistry. I also have another question: What is this chemical structure called? @@@H@@@H@@@H@@@ @@@|@@@|@@@|@@@ H----C-----C-----C----H @@@|@@@|@@@|@@@ @@@OH@@OH@@OH@@ Something like 1,2,3 trihydropropane?