neo_maya

http://www.earthtimes.org/articles/show/967.html Well... I don't know if you science-guys like it or not...... but just thought some of you might......

Guys, How do you solve this one? z^3 + Az^2 + Bz + C = 0 ; So far I have reached this solution ( resources from web of course ) w = (-f +- sqrt ( 27f^2 + 4e^3 )/ 27 ) / 2 * Substitution : z = y - b/3; y = x + s/x; s = -e/3; w = x^3; e = (c - b^2)/3 f = d + (2b^3/27) - (bc)/3;

Hmm........This dimension stuff is always kinda confusing. Here is one question - someone once told me that the fourth dimension is arbitrary (not necessarily time). I mean u can pick anything u want ( don't have a clue what that anything could be ) and assign it 4th dimension. Is it true?

Ohh........ I doesn't knew thet there waaasss thiscrimination against the foreign people in this site....... I mean go ahead and try using something other than ENGLISH..................then we will see.....

This one I think : http://en.wikipedia.org/wiki/Cubic_equation

http://mathworld.wolfram.com/MoebiusStrip.html http://astronomy.swin.edu.au/~pbourke/surfaces/mobius/ http://www.chessvariants.com/shape.dir/x_moeb.html Wow, sorry if this post doesn't seem relevant to u but some one said something about a Moebius Strip. Shame never heard of it before . I mean we all must have made this like a billion times before. Try making a Moebius Strip and cut it along the middle line. It's interesting. Try the links. Absolutely no idea about the math though. Don't quite see how a sphere can have infinite number of surfaces. And the concept of having zero surfaces is somewhat confusing too. I mean I see a sphere with two surfaces only.

Hey, It's the general discussion forum - so I am pretty much sure it wouldn't hurt anyone if I drop a few words about Harry. Has anyone ever been to the offcial Harry Potter site? I just did and sure it's one of the coolest. Do check out the trailer of the Prisoner of Azkaban. It's simply awesomoa............. Anyway, Just taking a break from science world - (goes back to it) and again greetings to everyone. Neo http://harrypotter.warnerbros.com/home.html

Er .. What's ur e-mail address ?

Correct me if I am wrong. I am supposed to think of those 6 digits in any order and it's supposed to be the right one to win a lottery !! BizzZZZZare idea for a scientific experiment. 87% just kinda sounds like a fluke - I mean (not being sarcastic or anything) there's isn't any scientific reason for that - is there? I mean it is the rule of probability that if you perform an experiment a countless number of time (infinite if possible) - then the number of the occurance of each possible result will be the same. And the fact that those numbers came up in that TV show souds like that it just happened to be their lucky day that the result matched. (probabilty inside probability) Don't ya get it. It's the machines that are making us believe. COUNT ME IN

Hi everyone, I kinda agree with sayo - there was no need for the other two sequels. The matrix alone was self-sufficient. It's true though that like everyone (........almost) else I was eager to watch the sequels. But they were indeed disappointing. Too much sfx and too much philosophy (especially in .......reloaded) made it somewhat almhskcfhliecr9qciwo4c. But the thing is that...... if .......... if there is a fourth one I would still go, despite knowing that it would be as dissappointing as the previous two. I think it's all my fault - I should have taken the blue pill (what can I say - then I would have missed trinity) . But on a second thought - IF I HAD TAKEN THE BLUE PILL THEN I THINK U ALL WOULD HAVE MISSED THE FIRST ONE - WHICH I THINK WAS LIKED BY ALL. I think there should be a poll about which pill should have been taken.

That's so true. I mean we're infact reading the posts on a monitor - and it is quite tough for the reader to read the post if it forms a big paragraph. I mean, of course - do post in details - but it would be really great for people like me who have spectacles - if u can just divide the posts in several paras. Maybe u wouldn't believe me - but I'm 17 - and I already have glasses - with -4.5 D power.

Dang..... have to find a new forum..... ..... Fooorrrr meeeeee?????!!!!. This is what u get in return of a good deeeeeed!!!! !!! People - follow the second link - this link can lead u to the path of freedom.......oops..sorry.....to the website of tickets for the movie......

Coming. [ Goog lord - should have come earlier - didn't know the members of SFN were so much hungry................ ]

LOL Daisy. U actually see peeps.. in the chatroom. Lucky u. - Whenever I enter the chatroom - it looks to me like I am the only serviver of the sky-net attack on this lonely planet. PS : Why are u so depressed about ur ...? Cheer Up. Actually this is going to be great - like u said - U will be hanging aroung a lot more than the usual!! Dudde say something!! Only u can cheer her up. And people - CHEER FOR MATRIX REVOLUTION.

Buckle up guys : It's "REVOLUTION" time. http://whatisthematrix.warnerbros.com/ http://www.fandango.com/movie_page.asp?mv=47558

atinymonkey???? http://www.lorencoleman.com/myakka.html Leave the big guys alone. Are they bothering us? I think not. Why bother them? Some more interesting stuff - [Go Tintin Go]

Is there any chance of a Matrix 4, like - The Matrix Backup or The MS Matrix XP or - Matrix reincarnated or something like that? Would u like to see a fourth one?

Keep Dancing http://www.123greetings.com/birthday/friends/bdayfriend10.html http://www.123greetings.com/birthday/birthday_wishes/wishes13.html

______________________________________ :flame: :stupid: :rant: :down: ______________________________________ :jk: [ I hope jk = just kidding ] ______________________________________ By the way - no no no no - BTW - How do u insert an image in a message ?

[ THENKS A LOT ]infinity

Thanks. http://www.geocities.com/mercutio78_99/c.html Check this out - A simple site (...I think) but I liked it - though didn't understand two of the machines' mechanisms. [ If perpetual motion is impossible - then why were so many attempts made? And I heard that people r still trying to invent such a machine. ]

I think this is how it is done : _______________________ T.E to convert ice at 0'C to water at 0'C = mlf T.E to convert water at 0'C to water at 100'C = mS d :theta: T.E to convert water at 100'C to steam at 100'C = mlv T.E = mlf + mS d :theta: + mlv = 15.25 * 106 J _______________________________________________ lf = Latent heat of fusion = 3.3 X 10^5 J/Kg S = C of Water J/Kg/K lv = Latent heat of vaporisation = 3.3 X 10^6 J/Kg Don't know the function of - specific heat capacity © of ice = C of steam = 2100 J\Kg\K I'm sure there's a mistake somewhere.

Is perpetual motion possible? I heard that it's impossible to make a machine that would start itself, generate power and continue working for as long as required, without any external energy. I heard that it has something to do with Newton's 3rd law and the fact that we can't generate anymore energy that we have. What is the function of perpetual motion anyway? And why is it impossible (/possible?) ?

HI, I had this small question about this problem. Here it is - I was just wondering - I always thought that .....amm... it takes at least two equations to solve a two variable problem. I mean, shouldn't there be another equation like y=x or y = 5x ? I thought that we can draw a graph with one equation and from there we can get the point where the curve intersects the x - axis. (Though I am not quite sure how we can draw one in this case) I mean I tried this - ln(x^y) = ln(y^x) => ylnx = xlny but couldn't go further to draw a graph. But I think graph is not the thing u want, right ?. So, my question is - can we solve one equation with two variables? If so, how ? If the procedure is complicated u don't have to explain it - just give the name of the preocedure or better if u can post a link. THANKS [ PS : How did u write y^x = x^y this way - yx=xy ]

Hey guys, I think I have solved the last one of my three posted problems. And no need to try to solve the limit problem. A friend of mine told me that it was not 1, it was -1. Don't know if any of u care but I would post the solution anyway since I think I have bugged u all enough with this. Here it is - ___________________________________________________ :int: (1/(sin^4 x + cos^4 x) dx = 4* :int: 1/ [ (2sin^2 x)^2 + (2cos^2 x)^2 ] dx = 4* :int: 1/ [ (1-co2x)^2 + (1+cos2x)^2 ] dx = 4* :int: 1/ [ 2+2cos^2 2x ] dx = 2* :int: sec^2 2x/ [ 2 + tan^2 2x ] dx ___________________________________________________ let, tan2x = z => 2sec^2 2x dx = dz ___________________________________________________ = :int: 1/ [ {2^(1/2)}^2 } + z^2 ] dx = [1/{2^(1/2)}^2 } ] * tan(inverse) [ tan2x / {2^(1/2)}^2 } ] + c TADA. Though couldn't solve the second one. Any idea about that one ?