neo_maya

:help:

Hmm, niether do I. But Thanks a lot for trying.

Don't tell me, don't tell me - Is it BY THE WAY?

Lol. Let, x^x = y => ln(x^x) = lny =>xlnx = lny =>d(xlnx)/dx = dy/dx =>x(d(lnx)/dx)+lnx(dx/dx) = (1/y)(dy/dx) =>1+lnx = (1/x^x)(dy/dx) =>x^x(1+lnx) = d(x^x)/dx So, d(x^x)/dx = x^x(1+lnx) EDIT : ___________________________________ PS : What is the meaning of BTW? I only know two of these shortcuts - LOL, ROFL.

lol. Mom thinks I am studying for the exam tomorrow. (If she finds out I'm looking at Sarah Brightman....................Amen) [ PS : Shhh I know who she's. Don't tell anyone - that was supposed to be a joke ] I'm chill.

http://www.sarah-brightman.com/index3.html [ Looked it up in GOOGLE. Haven't entered here yet. (ssh - mom's here - later.......) ]

hahaha err - who's he?

Hi, Thanks for replying Kedas. My hands r really tired. What I have written below is absolutely crap and has no meaning whatsoever. Please pardon me if I am wrong somewhere (if u actually have the patience to read this) and if u could kindly point that out, I will be really grateful. I am just trying to learn and check what I understand is right, nothing else. ___________________________________________________ I am new at this kind of stuff and don't yet (and never will) have a clear conception of these (especially limit). But, I saw a rule called L'Hospital's Rule which says something like this http://mathworld.wolfram.com/LHospitalsRule.html Now notice the first line where it states something like this - If lim [f'(x)/g'(x)] has a finite value ................................. _______________________________________________ I will come to this rule later _______________________________________________ What I am trying to say is this - in most of the cases of limit probs - we have to compute the value of a discontinuous function (at least what I understand) which doesn't have a real value if we put the value of the limit in the place of the function's variable. Most of the time, if we simply put the limit, then we will get a bizzare form of some sort like - 0/0 or infinity/infinity etc. Actually, the form is an indeterminate form. Meaning that you have'n determined the answer yet. This indeterminate form can be easily (?) circumvented by using algebraic manipulation. Such tools as algebraic simplification, factoring, and conjugates can easily be used to circumvent the form so that the limit can be calculated. ___________________________________________________ A simple example : lim {(x^3 - 27)/(x^2-9)} x->3 Now - if we just put 3 replacing x then we will get a form like 0/0. Thus, we can't compute it. But actually we can. We can cancel the (x-3) term and then compute it and the result is 9/2. There r lots of these examples - like when u work out the derivative of lnx. First u simplify lnx in its series (I think u get the series from maclaurine's theorem ? ) and then do some algebric manipulation and bang - u have the result (1/x). ___________________________________________________ Now my point is that all these examples had a form like 0/0 - yet they produce a result. I think (?) what we are doing here is that we first cancel that part of the function for which we get an indeterminant form and then we compute it. So, doesn't this mean that my limit problem has a solution too ? Now, look at this example lim a*{(x^3 - 27)/(x^2-9)} = 1 x->3 shouldn't we get the value of a = 2/9? __________________________________________________ Back to the L'Hospital's Rule - if I understood the rule right and what I did was right then u get the following form of my problem : ( ln a - 1 ) / ( lna + 1 ) = 1 => lna - 1 = ln +1 => nothing Here's my problem ???????? __________________________________________________

Hooow sweet and sooooo cute. Just like Dudde.

Hi, Were these questions posted here before? If so, then I am sorry and if someone can show me the link, I would really appreciate it. But I have searched the calculus forum, didn't find anything. I really need some help here. Thanks.

No offence.

I already have. Sayonara is a she !!!!!!!!!!!!!!??????????!!..........

lim (a^x-x^a)/(x^x-a^a) = 1 x -> a Then what is the value of a? :lint: (sinx/cosx)^1/2 dx [ Integration by parts? ] :lint: 1/(sin^4 x +cos^4 x) dx

Hey, I was having some problems with differentiation and integration. Can I post them now?

Ooooppppss. Right.

Hey, I think there should be a sqrt sign in the smilies list - don't you think?

IMAGINARY NUMBER. There are two modern meanings of the term imaginary number. In Merriam-Webster's Collegiate Dictionary, 10th ed., an imaginary number is a number of the form a + bi where b is not equal to 0. In Calculus and Analytic Geometry (1992) by Stein and Barcellos, "a complex number that lies on the y axis is called imaginary." Chech out these sites. There are a number of them out there. If u want I can search them for u. http://www.friesian.com/imagine.htm http://www.jimloy.com/algebra/imaginar.htm [These sites have long articles, but by the time u have finished reading them, I think that will do ] _______________________________________________ An Argand Plane is where u have to axis X and Y both intersecting each other at (0,0) point. X represents all the real numbers from -infinity to +infinity. And Y axis represents the imaginary numbers. ai + b = each and every number that u see. But in the case of real number a = o and in the case of imaginary number a has a value. So, every real number is a kinda imaginary number (sort of , where the imaginary part doesn't exist) only where a = 0. Cube roots of unity and their properties : :lcomega: ^3 = 1 1+ :lcomega: + :lcomega: ^2 = 0 where, :lcomega: = 1/2 {-1+ sqrt(-3)} and :lcomega: ^2 = 1/2 {-1- sqrt(-3)} There r a whole lot other stuff regarding i, but basically these are the basic ones. An imaginary number has some other properties like - if u multiply two conjugate imaginary numbers - u will get a real number or if u add them u will get a real number. And there is the modulus and argument of imaginary number. You can even work out the sqrt of [ 7-30sqrt(-2) ]. _______________________________________________ The problem with imaginary numbers are that - yet we can't define them. So, no matter how much we can imagine - we will never imagine an imaginary number until someone defines them or describes their characteristics or properties. But it is indeed a number - we just can't understand it - that's why it's imaginary (u have to imagine it). ________________________________________________ I don't know if each and every line of what I have written is right. But that's basically what can think of an imaginary number. PS : There r other forms of undefineables (I think) like - 0/0 , infinity/infinity. 0^0, infinty^infinity etc.

Thanks a lot.

I think we have just started travelling backward in time.

So, what now - my life's miserable and don't want to live antmore in this dirty and ugly world - I should commit suicide? How can u people even think of letting someone commit suicide?

First, u tell me - what's outside of this universe?

Ok - I read this in a scinece-fiction book - if u take a right handed golves outside of the universe and then bring it back - it will be left-handed. - Is there any scientific basis of this theory.

Oooooppsss sorry - got the point of the ever increament of entropy now. So, basically entropy refers to the disorder in the universe - but what is the heat death then?

Hey don't attack me - I'm just a crappy head. But here is how I see this - No - it wouldn't fit into a function catagory either. Like the illuminated one said - it's just ........i. And what I understand is - +ve infinity means a number greater than the largest number u can think of and -ve infinity means a number smaller than the smallest number u can think of. Though this brings the question - I heard there were 7 special forms like 0/0, infinity/infinity, 0^0 and several others that can't be defined. And they don't fit even into the catagory of infinity. They are like i, just imaginary. [ Someone please book a sit for me in the mental hospital , I am mad ]

But if a certain amount of energy is not ordered or useful - then wouldn't that energy transform to some other form of energy? Then why is it irreversible?