Hi all,
I'm trying to solve this differential equation but I'm getting strange results. Don't know how type all the symbols so I hope it makes sense.
dy/dx + 3y = 6
dy/dx = 6 - 3y
1/(6 - 3y)(dy/dx) = 1
1/(6 -3y)dy = dx
if I integrate both sides
(-1/3 )ln[6-3y] = x + C
boundary cond. when y=3 x=0
to find C, I substitute
(-1/3)ln[6-3(3)] = C
ok, this is where I'm stuck. Do I take C to be zero in this case.
Also, does anyone know of a website where I can get a simple and easy introduction to first order linear differential equations?
Thanks
