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Please could you tell me how to integrate tan^3[x] without integration by parts. i know that tan^2x = sec^2 x - 1 thanks in advance.

thanks. ive worked it out now...

This is probably really easy for all you guys, but I can't see the answer: Given that log 2 = 0.3, show that log 5 = 0.7 Thanks in advance.

^assuming that is correct^ 31131122211311123113321112131221123113112211121312211213211321322112311311222113311213212322211211131221221113222123211211131211121311121321123113112221231221322113112211

the thing is, this was set as a sort of 'brainteaser' question, so i was wondering if there was a simple, almost 'sneaky' way of doing it...

11131221131211131231121113112221121321132132211331222113112211 - i think...!

Does anybody have any ideas on how to work out [imath]\sqrt{0.9}[/imath] without a calculator (to approx 10 d.p.)? I know there are a few methods for working out for working out square roots by hand, but i was wondering if there was a cleverer/easier way of doing it.

- that's true. I originally saw this proof for 'teletubbies', for which it worked, because they were the PRODUCT of time and money (hence multiplication)...

actually' date=' [math']\pi=\frac{circumference}{diameter}[/math]

i was wondering if somebody had any ideas about this: the gradient of a horizontal line = 0 the gradient of a vertical line = infinity but the product of the gradients of perpendicular lines is -1 so does that mean that 0 x infinity = -1 ??? ... or is there something in the proof for the product of the gradients equalling -1 which excludes it for these values?