eva

In a ring pattern from selected area electron diffraction (SAED), does anyone know how to calculate the camera length? We are given everything except the d-spacings. The radius are just measure with a ruler. L(cam)=d*R/lambda R=Ltan(2theta) there is absolutely nothing out there on the net

Haha i can see that I should have done 50 mg/L * 0.1277. I'm going to start again. I didn't see that and nobody else did but thank you, sometimes you need someone to point out the obvious

Hi I need someone to explain to me what I have done because I confused my self. - I have a metal complex with 12.77% Fe in it - I wanted 50 ppm concentration of it: (50 mg/L)/0.1277=391.5 mg/L - I analysed it with AAS and it gave me a conc. of 39.2 mg/L - What does this mean? Should my AAS reading have been close to 391.5 like I calculated it? I don't understand my results at all. Maybe my procedure was wrong? PLEASE HELP

Yeah thanks but that didnt really help, you just told something I knew already. I worked it out anyway. 60 was the correct number. Thanks anyway

Cheers, I got it now. I was overcomplicating it in my head. It's for a tem image that I got given. Thanks again

Does anyone get how to find the magnification of a specimen just by having lattice spacing as a clue? I don't know any formulas so I don't know how to solve it.

For p1d1: p -> m(l)=-1,0,1 and m(s)=+1/2,-1/2 d-> m(l)=-2,-1,0,1,2 and m(s)=+1/2,-1/2 When I did the table, I got 60 microstates. I was wondering if it was correct because I don't know how to enter it in the n(microstate) equation. I don't know if i=8 and j=2 or i=5 and j=2 and neither of them give me 60 anyway. Could you please explain what I'm doing wrong there?

Hey dude, you can. Where I work, there is an environment exhibition and they've got one with a portion of a dance floor that absorbs energy with springs. They use that energy to play music and use the lights.

Cool I think I'm getting the idea. Will look up the reference if I get too stuck. Cheers for clearing that up

Is it just that what's inside the square bracket cannot break its bonds but the counter ion on the outside can? I just read about the dissolution of a coordination compound in water, does that mean just the counter ion would react if there were brackets?

Hey there I'm a 3rd year nanotechnology student and I'm trying to immerse myself in science. I'm Eva and I'm new so looking forward to discussing some stuff with you guys!