Jump to content

dslc1000

Senior Members
  • Posts

    36
  • Joined

  • Last visited

Everything posted by dslc1000

  1. (...If you feel (or even better - can prove) that anything I’ve written here is actually illogical, incorrect or that the values I’m using are inaccurate, please don’t hesitate to let me know...Otherwise, I’d love to hear if you agree with me...If so, we could discuss...) In almost all circumstances, the images which fall on a persons retina are inverted. Because we don’t see our world upside-down however, the obvious conclusion is that the ‘act of seeing’ (perhaps for want of better terminology) does not take place at the retina, but in our brain, once it has somehow re-inverted the image - so that we see it upright. I think most people would accept a corollary to this theory: if the image formed on the retina was upright, then what we actually ‘see’ must be inverted - as the brain has ‘learnt’ to invert everything we see. But how can this corollary be tested? Very simply actually! The reason that the image formed on our retinas is inverted is because of the refraction which occurs when light passes from air into the cornea and aqueous humour at the front of the eye, and also when light passes through the biconvex lens. If the refractive power of the cornea/aqueous humour is removed, however, the refractive power of the lens is not enough to invert the image by itself. The value I’ve been able to obtain for the refractive power of the lens is 20 diopters at maximum (which means that parallel rays striking it would be focused at a distance of 5 cm - 1/20 meters - behind it). A very simple way to remove the refractive power of the cornea/aqueous humour is to replace air with water. The reason this works is because water and the aqueous humour have almost exactly the same refractive index - that of water is usually given a value between 1.33 and 1.34; that of the aqueous humour is 1.336. What about the cornea? Well, the cornea has a refractive index of about 1.38, but this is irrelevant, as the opposite sides of the cornea can be considered as parallel for the purposes of this experiment (unlike the biconvex lens). Parallel rays travelling from water to the aqueous humor can therefore be considered as behaving as demonstrated in the attached "fig1.gif" Because the refraction occuring between the two mediums (water and the aqueous humor) in this instance is effectively negligible, rays which are parallel at the cornea can be considered to be still parallel at the lens (see attached "fig1.gif"). Values I’ve been able to gather for the refractive power of the lens vary - anywhere from 10 (or even below) to 20 diopters. Therefore, parallel rays striking the lens will be focused 5-10 cm behind the lens. The distance from the lens to the retina, however, is only 1.4-1.7 cm. The image of the object in the water, therefore, is upright on the retina. According to the prevailing theory of visual awareness, we should therefore see the object upside-down, as our brain is supposed to invert whatever image is formed on the retina. Try the experiment yourself! Take any object small enough so that the rays of light reflected off it into your eyes are parallel when the object is held at an arms length (or less) from your eyes, and which also has two easily-distinguishable sides (e.g. one side red; the other side white). Now submerge yourself in either fresh water or salt water (your bath; the sea; whatever - the difference between the refractive index of the two mediums is negligible - and no, this is not a joke ). Now simply hold the object out in front of you (at a distance which ensures that the rays reflected off it into your eyes are parallel). It is difficult to see under water - quite a strain on the eyes in fact - but if the object you are using has two easily-distinguishable sides, you will see the image upright, although, according to the prevailing theory of visual awareness, it should be inverted. Note that you don’t even see a diminished image of the object (which is the very least you would expect). (....These are my own original ideas, and I can readily verify this...don’t do anything silly like claim them as your own....) EDIT (May 7th 2004): This is sooooh embarassing , but it turns out that my argument is inherently flawed. See THIS thread to see where I went wrong.
  2. What does consciousness consist of? Sensations, thoughts, memories, ideas and emotions. The defining characteristic of any ‘thought’, whether it be an evaluation, intention, fancy or whatever, seems to be its mode of representation. What is common to all thoughts is that they are represented either as (i) imagined sensations, or (ii) silent words. Yet silent words are actually imagined sounds. Thoughts, therefore, are imagined sensations. Yet delcarative memory actually consists of imagined sensations as well. The same can be said for ideas, which are represented as pictures, sounds or words in our minds. As pointed out already, these are all imagined sensations. We have an interesting prospect, i.e. that thoughts, memories and ideas are all imagined sensations. What about emotion? Well, I propose that an emotion has two components: (i) sensation of the physiological changes belonging to a particular emotion (James-Lange theory of emotion), and (ii) the imagined sensation – the pictures, sounds or silent words which accompany the physiological changes. If this hypothesis is correct, and if what people refer to as thoughts, memories and ideas really are imagined sensations, then consciousness itself seems to have two components, namely: (i) sensations, and (ii) imagined sensations Note: I would categorize dreams as a sensation (as opposed to merely an imagined sensation). (These are my own ideas; and I can readily verify this)
  3. I think it must be the case that it can be Cap'n Refsmmat, but I'm not sure how.
  4. Hi! I have one specific question. Can anyone tell me what the refractive power of the lens is (...the one in the eye that is...)? I'm mostly interested in the maximum refractive power it can reach during accomodation. I've done a few google searches on it, and found some stuff, but it seems to contradict what I have in my own textbook. My textbook says a dozen diopters, while a website I have just visited states that the upper limit during accomodation is ten diopters, while the lower limit is infact zero diopters! (..I might have even read twenty diopters somewhere...although that doesn't seem right...) What I basically want to know is: if two parallel rays were to strike the lens during maximum accomodation (i.e. when its refractive power is greatest) , how far behind the lens would they be focused? Thank you for taking the time to answer such an odd question! (...if anyone does...)
  5. I think that the bacteria do hinder us. First of all, bacteria in sweat are responsible for an unpleasant odour. I know this isn't a permanent effect, but it is a negative effect nonetheless. As for the bacteria in plaque, well they clearly have a negative effect – they attack tooth enamel - and it can be a permanent one.
  6. Sorry MrL_JaKiri, I should have been more specific. What I really want to know is: do these bacteria serve any useful purpose for the human body? E.g. is it necessary for the components of sweat to be broken down so it will evaporate more rapidly?
  7. I have a few specific questions - all in relation to nice things like bacteria, sweat and plaque. (You might want to postpone reading this post until after your dinner. ) I am aware that sweat itself is actually odourless, and that the unpleasant smell actually comes from the byproducts of bacteria feeding on the sweat. When I discovered this, I was led to ask myself: does the gram positive bacteria which breaks up the molecules in sweat actually serve any useful purpose? Anyone know? Also, does anyone know if the bacteria in saliva - the ones which from plaque on teeth surfaces - has any useful purpose? And does anyone know how the bacteria in the saliva actually got there - e.g. via the food a person eats?
  8. Thanks fafalone, but I'm not sure that's the information I was looking for. What I meant to ask was 'how many actual rhodopsin molecules are there per photoreceptor, i.e. embedded in the discs of the photoreceptor outer segments?' Are you saying that there are only three in cones, and one in rods?
  9. I have a few specific questions: (i) How many photopigments are then in a typical rod and a typical cone? (ii) Does the number vary? If so, in what range?
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.